Global Extrema/Area of a Rectangle

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Homework Help Overview

The problem involves finding the dimensions of a rectangle with a fixed perimeter of 200 meters that maximizes the area. This falls under the topic of Global Maxima/Minima in calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equations for perimeter and area of a rectangle, with attempts to express the area in terms of a single variable. Questions arise about how to apply the perimeter constraint to maximize the area function.

Discussion Status

Participants are actively engaging with the problem, sharing insights and clarifying concepts. Some guidance has been provided on how to express the area as a function of one variable, and there is a sense of progress as participants work through the relationships between the dimensions.

Contextual Notes

There is an indication of frustration from the original poster regarding the clarity of the textbook, which may be impacting their understanding of the problem setup and solution approach.

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Homework Statement


Find the dimensions of of the rectangle with perimeter 200 meters that has the largest area.


Homework Equations





The Attempt at a Solution


This is in the section on Global Maxima/Minima so I know it has to be something with graphing a formula and finding the maxima, but I cannot figure where to start on this. The book is no help (Applied Calculus - Hughes-Hallett, et.al) and this is not the first time it has presented problems that it does not even began to describe in the text.

Can someone tell me where to start?
 
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What is the equation for the perimeter of a rectangle with length x and height y (and what do you have to set this equal to)? What is the equation for the area of this rectangle?
 
Dunkle said:
What is the equation for the perimeter of a rectangle with length x and height y (and what do you have to set this equal to)? What is the equation for the area of this rectangle?

Ok, so I have 200=2(x+y), and the area is A=xy, right? I must be missing something terribly obvious, because I am still stuck on where to go from here, except that maybe 100=x+y. How does this fit into a Global Extrema problem?
 
Okay, good! Now, you need to write the area in terms of just one variable so that you can find the maximum of the area function. Any ideas?
 
y=A/x? Man, I can almost get this, I feel like I'm so close, but where does the perimeter function come in, y=100-x?

Is this problem an an easy one? Because it seems like it, and it's making me feel so dumb that I can't figure it out!
 
You are so close! You are trying to maximize the area, so you need to write the area as a function of x (or y) only. You can solve for x in terms of y (and vice versa) using the perimeter constraint. 2x+2y = 200 => y = 100-x => A = x(100-x). Now how do we find the value of x when this function is at its maximum? Once you find this x, you can solve for y using the relationship we found between x and y using the perimeter constraint. Is this clear?
 
50x50! Dude, thanks for your patience on that one, it was driving me crazy! It makes sense now.
 
You're welcome! Also, note that this answer may have been what you expected from the beginning: a square!
 

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