The gradient of the curve C is given by: dy/dx = (3x-1)(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}

the point P (1,4) lies on C.

a) Find an equation of the normal to C at P.

b) Find an equation for the curve C in the form y=f(x)

c) using dy/dx = (3x-1)^{2}show that there is no point on C at which the tangent is parallel to the line y=1-2x.

Well for a) i got: 4y= -x+17 (subbed x= 1 in dy/dx, got grad of normal and got eq)

But, i don't understand what part b) wants me to do. I think i could do c) by using the gradients and showing that they're not the same.

Some help on b) please!

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# Gradient of the curve help

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