Gradient of the dot product of two vectors that are the same

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SUMMARY

The discussion focuses on finding the gradient of the dot product of two identical vectors, specifically the expression ∇(E · E), where E represents the electric field defined as E_{0}(exp(i(kx-ωt))). It is established that since the vectors are identical, E · E simplifies to ||E||². The correct approach involves calculating the gradient of the magnitude squared, leading to the expression 2ikE_{0}². Participants emphasize using vector identities and partial derivatives to derive the solution accurately.

PREREQUISITES
  • Understanding of vector calculus, specifically gradient and dot product operations.
  • Familiarity with complex exponentials in the context of electric fields.
  • Knowledge of partial derivatives and their application in vector functions.
  • Basic grasp of electromagnetic theory and electric field representations.
NEXT STEPS
  • Study vector calculus identities, particularly those related to gradients and dot products.
  • Explore the derivation of gradients in complex fields, focusing on expressions involving exponential functions.
  • Learn about the implications of electric field representations in physics, especially in wave mechanics.
  • Review applications of partial derivatives in physics and engineering contexts.
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism, vector calculus, and mathematical methods in physics. This discussion is beneficial for anyone looking to deepen their understanding of gradients in vector fields.

wobblybird
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Hi,

I am trying find the simplified expression of this:
∇(E \cdot E)

Where E is the electric field that can written as E_{0}(exp(i(kx-ωt))

I know that since the two vectors are the same => E \cdot E = ||E||^{2}

Do I take the gradient of the magnitude then? It just doesn't feel right. Or should it be something like 2ikE_{0}^2?

Thank you so much!
 
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You can just take the gradient of the square of the magnitude - write it out as a function with no vectors involved, and calculate partial derivatives
 

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