Gradients and level curves, getting started with my homework

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Homework Help Overview

The discussion revolves around the computation of gradients and level curves for the function f(x,y) = y - x. Participants are tasked with finding the gradient vector at a specific point and understanding the relationship between the gradient and level curves.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the computation of the gradient and its evaluation at the point (2,1). There is confusion regarding the nature of level curves and how to derive them from the given function. Questions arise about whether the gradient vector remains constant and how to visualize the relationship between the gradient and level curves.

Discussion Status

Some participants have provided insights into the nature of the gradient and level curves, suggesting that the gradient field is constant. Others have attempted to derive the equation for the level curve and are exploring the geometric relationship between the gradient vector and the level curve. There is an ongoing examination of how to prove the orthogonality of the gradient vector to the level curve.

Contextual Notes

Participants mention a lack of clarity due to missed class time and express uncertainty about the expectations for the level curve and gradient vector. There is also a reference to previous class discussions on level curves, indicating a potential gap in understanding the current assignment.

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Homework Statement


f(x,y)=y-x
i) compute the gradient
ii) at the given point (2,1) compute the gradient vector gradf(2,1)
iii) compute the level curve that passes through the point (2,1)
iiii) on the xy-plane, sketch the level curve from iii and the gradient vector gradf(2,1) you found in ii. Verify that they meet orthogonally


Homework Equations


gradients, derivatives, etc.


The Attempt at a Solution



I was out sick all last week from class so I need a little leg up on what we are doing...

for i) wouldn't this just be <-1,1> ?
and if so, I'm a little confused on ii) which I assumed to be <-1,1> still regardless of what point it was 'evaluated' at.

And then from here I'm not sure how to compute the level curve for this. Am I looking for a vector, equation, scalar? Before this when we talked about level curves in class, we were always given a set of constants to set them equal to.

And as far as iiii) goes, I'm a bit confused what this is supposed to look like since ii) would always be the vector <-1,1>
 
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sheepcountme said:

Homework Statement


f(x,y)=y-x
i) compute the gradient
ii) at the given point (2,1) compute the gradient vector gradf(2,1)
iii) compute the level curve that passes through the point (2,1)
iiii) on the xy-plane, sketch the level curve from iii and the gradient vector gradf(2,1) you found in ii. Verify that they meet orthogonally


Homework Equations


gradients, derivatives, etc.


The Attempt at a Solution



I was out sick all last week from class so I need a little leg up on what we are doing...

for i) wouldn't this just be <-1,1> ?
and if so, I'm a little confused on ii) which I assumed to be <-1,1> still regardless of what point it was 'evaluated' at.

You are correct. In this example the gradient field is constant

And then from here I'm not sure how to compute the level curve for this. Am I looking for a vector, equation, scalar? Before this when we talked about level curves in class, we were always given a set of constants to set them equal to.

The level curves are f(x,y) = C for various constants C. But you are being asked for just one of them. Figure out C for your point and what equation do you get for your single level curve?

And as far as iiii) goes, I'm a bit confused what this is supposed to look like since ii) would always be the vector <-1,1>

So show the vector is perpendicular to the level curve in ii.
 
Okay, so for iii, setting y-x=c c is -1 when we plug in the given point which gives us the equation y=x-1.

but for part 4, y=x-1 is pretty much the line y=x but shifted 1 down and to the right, and the line I get for part 2 is a straight horizontal line across the plane, which isn't perpedicular to the level curve.
 
You don't get a line for part 2, you get a vector. Prove that the vector -1i+ 1j is perpendicular to the line y= x- 1. (One point on the line y= x- 1 is (0, -1). Another is (2, 1). What is the vector from (0, -1), to (2, 1)? It points in the same direction as the line.)
 

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