Gradients and Tangents to Level Curves

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Homework Help Overview

The discussion revolves around finding the gradient of the function f(x,y) = y - x at the point (2,1) and understanding the concept of level curves associated with this function.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of the gradient and express uncertainty about the concept of level curves. There are inquiries about the relationship between functions of two variables and their graphical representations, as well as the implications of extending to functions of three variables.

Discussion Status

Some participants have provided definitions and clarifications regarding level curves and the nature of gradients. There is an ongoing exploration of the implications of these concepts, particularly in higher dimensions, with no explicit consensus reached.

Contextual Notes

Participants are navigating the definitions and properties of gradients and level curves, with some expressing confusion about the dimensionality of functions and their graphical representations.

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Homework Statement


Find the gradient of the function at the given point, then sketch the gradient together with the level curve that passes through the point.

f(x,y) = y - x (2,1)


Homework Equations



gradient of f = (df/dx)i + (df/dy)j

The Attempt at a Solution



df/dx = -1
df/dy = 1

gradient of f = (df/dx)i + (df/dy)j = -i + j

I don't really know where to go from here; what exactly is a level curve?
 
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Quincy said:

Homework Statement


Find the gradient of the function at the given point, then sketch the gradient together with the level curve that passes through the point.

f(x,y) = y - x (2,1)


Homework Equations



gradient of f = (df/dx)i + (df/dy)j
Keep in mind that these are really partial derivatives.
Quincy said:

The Attempt at a Solution



df/dx = -1
df/dy = 1

gradient of f = (df/dx)i + (df/dy)j = -i + j

I don't really know where to go from here; what exactly is a level curve?
A level curve is a curve for which all points on the curve have the same function value (z-value in this case. Since the graph of your function is a plane in R3, level curves will be straight lines.

If you are familiar with topographical maps, each curve shown on the map is a level curve. Each point on a given curve is at the same altitude.
 
Mark44 said:
A level curve is a curve for which all points on the curve have the same function value (z-value in this case. Since the graph of your function is a plane in R3, level curves will be straight lines.
So, the value of a function with two variables is the value of z? In other words, f(x,y) = z? What about functions with 3 variables (f(x,y,z))?
 
Typically w is used for functions of three variables, with w = f(x, y, z). In fact, the particular letter doesn't matter; it just has to be different from the others.
 
Mark44 said:
Typically w is used for functions of three variables, with w = f(x, y, z). In fact, the particular letter doesn't matter; it just has to be different from the others.
But a graph can only have 3 dimensions, x, y, and z, so what is w supposed to represent?
 
Quincy said:
But a graph can only have 3 dimensions, x, y, and z, so what is w supposed to represent?
It's true that we can't readily visualize a graph in more than 3 dimensions, but there's no reason we can't generalize the notion to higher dimensions.
 
Quincy said:
But a graph can only have 3 dimensions, x, y, and z, so what is w supposed to represent?
Well, a graph can have more than 3 dimensions, it is just hard to draw in a 3 dimensional space!

One important property of the gradient, by the way, is that it always point in the direction of fastest increase and is always perpendicular to "level curves" (or level surfaces for functions of two dimensions). If you know a vector perpendicular to a line at a point, it is easy to give the equation of the line perpendicular to that vector and so tangent to the curve. And, of course, it is easy to use a vector perpendicular to a surface, at a point, to find the tangent plane to the surface at that point.
 

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