Graph Theory: Does a Graph Have Cardinality?

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A graph consists of a vertex set and an edge set, leading to the question of its cardinality. The cardinality of a graph is not simply the sum of its vertices and edges, as graphs are defined by two distinct sets rather than a single union. To discuss the cardinality of a graph, a specific definition is required, typically focusing on the vertex set. The common convention is to define the cardinality of a graph as the number of vertices it contains. This clarification helps in understanding the abstract nature of graph theory.
Charles Stark
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So as I was beginning to read through my Graph Theory textbook I had a burning question I wanted to get some perspective on.

So a Graph is defined as an object containing a Vertex Set and an Edge Set,

v = # of elements in the vertex set and e = # of elements in the Edge Set (if any)

Would this mean that |g| = v + e = cardinality of the graph?

Abstract thinking is strange to me sometimes and its weird to think of a graph technically having cardinality.
 
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Charles Stark said:
Would this mean that |g| = v + e = cardinality of the graph?

If a graph were a single set expressed as the union of two sets, you could infer that "cardinality of the graph" was the cardinality of that single set. However a graph is defined to have a pair of sets, vertices and edges. It is not defined as the union of those two sets. So if we want to talk about the "cardinality of a graph" we must create a special definition for it.

These folks say that the cardinality of a graph is customarily defined as the cardinality of its set of vertices:
http://math.stackexchange.com/questions/442843/a-cardinality-of-a-graph
 
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Ah ha! I was thinking of a graph as a set containing two sets. Thank you for the clarification!
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

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