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Graphing a function using calculus

  1. Sep 13, 2010 #1
    How would you graph the function:
    (x2-9)/(x2-4)

    I am having a lot of trouble finding the critical and hypercritical numbers without the aid of a graphing utility.
    Thank you very much!
     
  2. jcsd
  3. Sep 13, 2010 #2

    rock.freak667

    User Avatar
    Homework Helper

    Start by dividing out the polynomial to give you something like:

    y=f(x) + (something)/(x2-4)

    Then factor (x2-4) and see what happens as x→±2.
     
  4. Sep 13, 2010 #3

    Mark44

    Staff: Mentor

    To get the critical numbers, find the derivative of (x^2 - 9)/(x^2 - 4). The critical numbers are those for which the derivative is zero.
     
  5. Sep 13, 2010 #4
    yea, i understand that, but I calculated the second derivative to be (-30x2-40)/(x2-4)3, which has two asymptotes at 2,-2, but the top of this fraction can never equal zero and I end up with imaginary numbers. How do you solve for concavity with imaginary numbers?
     
  6. Sep 13, 2010 #5

    Mark44

    Staff: Mentor

    Where is the first derivative equal to zero? You seem to have skipped right over that step.

    I got the same as you for the second derivative, so that would suggest that we're both right. The numerator is always negative for any real number, but the denominator can be positive or negative, depending on whether |x| > 2 or |x| < 2, respectively. That tells you the intervals where the graph of the function is concave up or down.
     
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