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Gravitational force on inclined plane

  1. Feb 25, 2009 #1
    1. The problem statement, all variables and given/known data

    You place a box weighing 265.5N on an inclined plane that makes a 43.2 degree angle with the horizontal. Compute the component of the gravitaltional force acting down on the inclined plane.

    2. Relevant equations

    m x g x cos(degree)

    3. The attempt at a solution

    265.5 x 9.8 x cos(43.2)

    The answer came out incorrect. I think I calculating the wrong force the question confuses me.
     
  2. jcsd
  3. Feb 25, 2009 #2
    Re: Forces

    Try drawing the picture. You need to think the geometry through rather than just trying to plug numbers into formulas.
     
  4. Feb 25, 2009 #3
    Re: Forces

    still very confused do you mean a free body diagram ?
     
  5. Feb 26, 2009 #4
    Re: Forces

    An FBD should do the job. Perhaps you are confused by the wording. The words, "component ... acting down on the inclined plane" refers to the force normal (perpendicular) to the plane.
     
  6. Feb 26, 2009 #5
    Re: Forces

    So wouldnt the Normal force be the same as the mass because the inclined plane is holding it up ?
     
  7. Feb 26, 2009 #6
    Re: Forces

    Which direction is the weight?
     
  8. Feb 26, 2009 #7
    Re: Forces

    straight down ?
     
  9. Feb 26, 2009 #8
    Re: Forces

    since when is mass measured in newtons?
     
  10. Feb 26, 2009 #9
    Re: Forces

    thats what im saying wouldnt the Normal force be W=mg ?
     
  11. Feb 26, 2009 #10
    Re: Forces

    ok so.. 265.5 = m 9.8

    m = 27.1N

    27.1 x 9.8 x cos(43.2) = 193.6 N = Fn ????
     
  12. Feb 26, 2009 #11
    Re: Forces

    Newton's aren't a unit of mass

    Otherwise, it looks ok to me.
     
  13. Feb 26, 2009 #12
    Re: Forces

    193.6N isnt the correct answer im still stumped
     
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