Gravitational Force on Mass in Cavity of Planet

AI Thread Summary
The discussion focuses on calculating the gravitational force on a small mass located at the center of a spherical cavity within a planet. The planet has a radius R and a density d, while the cavity has a radius of R/2 and is positioned at a distance of R/2 from the planet's center. Participants are attempting to derive the gravitational force using the formula F = Gm1m2/r^2, but there are discrepancies in their calculations, with one participant arriving at 16Gpidrm/3 and another at 2Gpidrm/2. A key insight shared is to treat the cavity as filled and then subtract the gravitational effect of the cavity, leading to a correct understanding of the gravitational field inside a uniform spherical shell. The conversation highlights the importance of proper application of gravitational principles in complex geometries.
anshuman3105
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A large spherical planet of radius R made of a material of density d, has a spherical cavity of radius R/2, with center of cavity a distance R/2 from the centre of the planet. Find the gravitational Force on a small mass m at the centre of the cavity
 
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anshuman3105 said:
A large spherical planet of radius R made of a material of density d, has a spherical cavity of radius R/2, with center of cavity a distance R/2 from the centre of the planet. Find the gravitational Force on a small mass m at the centre of the cavity
As per forum rules, you should quote any relevant standard equations of which you are aware and must show some attempt at a solution. If totally stuck, you should at least be able to provide some thoughts.
 
using the formula F = Gm1m2/r^2, i am getting 16Gpidrm/3 but the solution is 2Gpidrm/2
 
anshuman3105 said:
using the formula F = Gm1m2/r^2, i am getting 16Gpidrm/3 but the solution is 2Gpidrm/2
I get ##\frac 23 G\pi d r m## (I'm guessing the "/2" in what you posted is a typo).
Please post your working.
(There is a very quick method here.)
 
Yes your answer is right...but how did you do it?
 
I used Gm1m2/r^2
So F = (G(d*4/3pir^3)m)/(r/2)^2
 
anshuman3105 said:
I used Gm1m2/r^2
That formula is essentially for point masses. It also works if one mass is a uniform spherical shell (or assembly of concentric uniform spherical shells) and the other (point) mass is outside all the shells.
The trick when dealing with cavities is to treat the cavity as filled in (i.e. no cavity) then add a 'negative mass' at the cavity. so in this case we have a complete sphere (S1) radius R minus a complete sphere (S2) radius R/2.
What do you know about the gravitational field inside a uniform spherical shell?
What is the force on m due to S1?
What is the force on m due to S2?
 
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Can you show it to me the solved part..?
 
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