Gravitational pull of Earth and escape velocity

AI Thread Summary
Escape velocity allows an object to move away from Earth without being pulled back, but Earth's gravity continues to act on it, slowing it down over time. While the object will not stop completely, it will asymptotically approach zero velocity relative to Earth as it moves further away. Escape velocity is not a constant; it decreases with distance from Earth, meaning the object will always be slowing down at the escape velocity specific to its current distance. The concept of "hyperbolic excess velocity" is relevant in understanding this gradual deceleration. Overall, the object's trajectory is influenced by both Earth's gravity and other celestial bodies as it travels through space.
Zynoakib
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I know once the escape velocity is reached, the object will continuous to move away from the Earth. But the Earth's gravity can still act on the object no matter how far it goes, so what keeps the object from stopping or even returning back to Earth?

Thanks in advance!
 
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Zynoakib said:
I know once the escape velocity is reached, the object will continuous to move away from the Earth. But the Earth's gravity can still act on the object no matter how far it goes, so what keeps the object from stopping or even returning back to Earth?

Thanks in advance!
It is inherent in the equations of motion. The object does slow down some but not down to zero. That's really the definition of escape velocity; giving an object sufficient velocity that gravity never quite overcomes it. Mathematically, when it gets to infinity it has zero velocity relative to the Earth (assuming it left with exactly the escape velocity), but of course in reality it will be more affected by celestial bodies other than the Earth WAY long before then (and the infinite "then" never actually occurs in reality)
 
phinds said:
It is inherent in the equations of motion. The object does slow down some but not down to zero. That's really the definition of escape velocity; giving an object sufficient velocity that gravity never quite overcomes it. Mathematically, when it gets to infinity it has zero velocity relative to the Earth (assuming it left with exactly the escape velocity), but of course in reality it will be more affected by celestial bodies other than the Earth WAY long before then (and the infinite "then" never actually occurs in reality)

Just want to explain it in my own wording

Although the Earth's gravity can still attract the object to slow it down no matter how far it goes, it will take forever for the object to be slowed down just by a slight degree.
 
Zynoakib said:
Just want to explain it in my own wording

Although the Earth's gravity can still attract the object to slow it down no matter how far it goes, it will take forever for the object to be slowed down just by a slight degree.
No, that's not a good way to say it. It will take forever for it to be slowed to zero.
 
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phinds said:
No, that's not a good way to say it. It will take forever for it to be slowed to zero.
So, note that escape velocity is not a single/constant value. It decreases with distance. So an object that is launched exactly at escape velocity will always be slowing down, and will always be at the escape velocity of whatever distance it is at.
 
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russ_watters said:
So, note that escape velocity is not a single/constant value. It decreases with distance. So an object that is launched exactly at escape velocity will always be slowing down, and will always be at the escape velocity of whatever distance it is at.
Agreed for sure.
 
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"Hyperbolic excess velocity" is what you're looking for here.
 
Thanks guys, now I understand
 
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