Gravitational Time Dilation Problem

J_M_R
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Homework Statement



A person lived 75 years in a city located 3.1km above sea level. How much longer could they have lived at sea level? (Times are measured by an observer at infinite distance).

Homework Equations



tr/t∞ = {1 - [ (2GM) / (r(c^2)) ]}^(1/2)

Rc (Radius at city) = Rearth + 3.1km

∴ t(sea-level)/t∞ = {1 - [ (2GMe) / (Rearth(c^2)) ]}^(1/2)

and ∴ t(city)/t∞ = {1 - [ (2GMe) / (Rc(c^2)) ]}^(1/2)

The Attempt at a Solution



t(sea-level) / {1 - [ (2GMe) / (Rearth(c^2)) ]}^(1/2) ≈ t(city) / {1 - [ (2GMe) / (Rc(c^2)) ]}^(1/2)

Having made the the two t∞ equal to each other.

Knowing t(city) = 75 years this gave t(sea-level) as 74.99 years.

Where have I gone wrong as shouldn't t(sea-level) be longer?
 
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J_M_R said:
Where have I gone wrong as shouldn't t(sea-level) be longer?

What gives you that idea?
 
PeroK said:
What gives you that idea?

I was just using the fact that the question says "How much longer could they have lived at sea level?" so assumed t(sea-level) should therefore be longer?
 
J_M_R said:
I was just using the fact that the question says "How much longer could they have lived at sea level?" so assumed t(sea-level) should therefore be longer?
Ask yourself, which of the two has longer until his 76th birthday according to your calculations.
 
Bandersnatch said:
Ask yourself, which of the two has longer until his 76th birthday according to your calculations.
Ah, so the t(sea-level) has longer until his 76th birthday so the person could have lived 0.01 years longer at sea level according to my calculations?
 
You got it.
 
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Bandersnatch said:
You got it.
Thanks!
 
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