Gravity of the Earth if its mass were doubled

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SUMMARY

The gravity on the surface of the Earth, if its mass were doubled and its radius halved, would be calculated using Newton's law of universal gravitation. Specifically, the gravitational force can be expressed as F = G * (m1 * m2) / r². Doubling the mass (m1) and halving the radius (r) results in an increase in gravitational force by a factor of 16, due to the inverse square law. This scenario leads to a significant increase in density, raising questions about the feasibility of such a planet's formation.

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Albert einstine
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New user's thread moved to the Homework Help forums (it is for self stucy), so no Template is shown
What would be the value of gravity on the surface of the Earth if its mass was twice as large and its radius half of what it is now?
 
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Albert einstine said:
What would be the value of gravity on the surface of the Earth if its mass was twice as large and its radius half of what it is now?
Welcome to the PF. :smile:

What have you found for the equation for gravitational force in your searching and reading so far? Also, is this a schoolwork question?
 
Your question leads to a density increase by a factor of 16, What would you use to make such a planet?
 

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