Green's Function Homework: Real & Imaginary Parts

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SUMMARY

The discussion focuses on calculating the real and imaginary parts of Green's function, specifically the expression g00 = [1 - (1 - 4t²(z - E₀) - 2)¹/²] / (2t²(z - E₀) - 1). The user initially struggled with separating the real and imaginary components but received guidance on using polar coordinates to simplify the square root. The hint provided by a forum member, involving the conversion of the square root to polar form, proved effective in resolving the issue.

PREREQUISITES
  • Understanding of complex numbers, specifically the form Z = x + iy.
  • Familiarity with Green's functions in mathematical physics.
  • Knowledge of polar coordinates and their application in complex analysis.
  • Basic algebraic manipulation skills, including handling square roots in equations.
NEXT STEPS
  • Study the properties of Green's functions in quantum mechanics.
  • Learn about polar coordinates and their role in complex number analysis.
  • Explore techniques for separating real and imaginary parts of complex functions.
  • Investigate advanced algebraic methods for simplifying expressions involving square roots.
USEFUL FOR

Students and researchers in mathematical physics, particularly those working with Green's functions and complex analysis. This discussion is beneficial for anyone looking to enhance their understanding of separating complex expressions into real and imaginary components.

Mancho
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Homework Statement



I'm asked to calculate Green's function's real and imaginary parts.
The expression for the given Green's function is:

g00=[1-(1-4t2(z-E0)-2)1/2]/2t2(z-E0)-1 (1)
Where, z is the complex variable: z= E+iO+ (2)

Homework Equations



Complex number definition: Z = x + iy, where x is the real part and iy - imaginary.

The Attempt at a Solution


To separate real and imaginary parts I tried to express g00 in the form: g00= x+iy

First I simplified the (1) by multiplying the denominator and numerator by (z-E0).
The result is g00= 1/2t2[(z-E0)-(1-4t2)]1/2.

Then I'm stuck. I don't know how to remove the square root to divide real and imaginary parts. I'm not even sure if it is the pure math problem or if I have to take into consideration anything else.

I would appreciate any help.
 
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Welcome to PF!

Mancho said:
I'm asked to calculate Green's function's real and imaginary parts.

I don't know how to remove the square root to divide real and imaginary parts.

Hi Mancho! Welcome to PF! :smile:

Hint: the square-root of re is (√r)eiθ/2, and so its real and imaginary parts are (√r)cos(θ/2) and (√r)sin(θ/2) :wink:
 
Thanks a lot tiny-tim!

I guessed from your hint I had to use polar coordinates and it worked great! I got what I was supposed to. Maybe I will upload the solution later when I have time.

Thanks again! :)
 

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