Griffiths E&M Problem 3.15: Solving a 3D Bounded Region

[ehrenfest]

Homework Statement

This question refers to Griffiths E and M book.

Homework Equations

The Attempt at a Solution

Obviously this is a 3D problem and we should use Example 3.5 as a model. However, since the region of interest is bounded in all 3 directions doesn't that mean that all of C_1, C_2, and C_3 need to be negative? But then C_1+C_2+C_3=0 is impossible! The constants C_i that I am referring to are on page 135.

 

[Mindscrape]

Laplacian

\nabla^2 V = 0

After separation of variables:

\frac{1}{F}\frac{d^2 F}{dx^2} + \frac{1}{G}\frac{d^2 G}{dy^2} + \frac{1}{H}\frac{d^2 H}{dz^2} = 0

Argument: How can a function of x and y and z added together be zero always?

 

[ehrenfest]

Laplacian

\nabla^2 V = 0

After separation of variables:

\frac{1}{F}\frac{d^2 F}{dx^2} + \frac{1}{G}\frac{d^2 G}{dy^2} + \frac{1}{H}\frac{d^2 H}{dz^2} = 0

Argument: How can a function of x and y and z added together be zero always?

That is my point! If
\frac{1}{F}\frac{d^2 F}{dx^2}=C_1
\frac{1}{G}\frac{d^2 G}{dy^2}=C_2
\frac{1}{H}\frac{d^2 H}{dz^2} =C_3

Then C_1 +C_2+C_3 must be 0 which means that not all the C_i can be negative, which is absurd because we need trig functions not exponentials since the region is bounded in all three directions??

 

[Mindscrape]

Absolutely, positive constants will give the trivial solution.

Why not say -C1-C2-C3=0? Does it really matter whether the constants we make are negative or positive, aren't they allowing the functions to *sum* to zero in either case?

 

[nicksauce]

Why not exponentials? It seems like the potential will start at Vo at z = a, then decay (exponentially) down the z axis.

 

[Mindscrape]

Try to apply the boundary conditions to exponentials. It may be easier if you write them in terms of sinh and cosh in this case.