Grignard Synthesis: Ph-Mg-X + tert-Butyl Alcohol

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The discussion centers on the reaction between phenyl magnesium halide (Ph-Mg-X) and tert-butyl alcohol. The initial assumption is that the product would be tert-butyl benzene, but it is clarified that the actual product is benzene. This occurs because the Grignard reagent acts as a strong base, deprotonating the alcohol rather than forming an alkylated product. The reaction leads to the formation of benzene and a magnesium alkoxide. Understanding the behavior of Grignard reagents with alcohols is crucial for predicting the correct products in these reactions.
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Homework Statement


Predict the product, along with the reaction mechanism,of the given reactants -:

Ph-Mg-X + tert-butyl alcohol \longrightarrow \ ?

My attempt
This is a grignard synthesis, RMgX where R is phenyl carbanion . The general reaction with water gives alkanes,and X-Mg-OH . Similarly the reaction with alcohol should give tertbutyl benzene and X-Mg-OH ? But the given answer is benzene.
Could someone give an explanation as to how that is being formed ?
Any links to webpages explaining griganard reactions with alcohols will also be appreciated.
Thx
 
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What is the product of a reaction between a grignard (strong base and sometimes alkylating agent) and an alcohol?

This statement is not correct:
Similarly the reaction with alcohol should give tertbutyl benzene and X-Mg-OH ?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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