Ground Velocity of Light Plane: Calculate & Solve

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To calculate the ground velocity of a light plane traveling at 175 km/h on a heading of N 8 degrees E, while facing a 40 km/h wind from N 80 degrees E, one must visualize the vectors involved. The plane's vector points mostly upwards and slightly to the right, while the wind vector is directed downwards and to the left. Drawing these vectors as lines in a triangle helps in understanding their relationship. The resultant vector, which represents the ground velocity, can be determined by connecting the origin to the endpoint of the wind vector. This approach simplifies the calculation of the plane's actual ground speed and direction.
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1. A light plane is traveling at 175 km/h on a heading of N 8 degrees E in a 40km/h wind from N 80 degrees E. Determine the plane's ground velocity.



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The Attempt at a Solution


Im having problems drawing the vector, i am not to sure at how it looks. if someone could help me draw it, and just a brief outline on how to solve the question.
 
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So your plain is going almost straight "up", and slightly to the right. The wind is blowing down and left, mostly left (wind is FROM N by E, not blowing to there).

So you should draw Line 1 going from your origin, mostly up and slightly to the right. Line 2 starts at the end of Line 1, is shorter than Line 1 (about 1/4th as long), and is going mostly to the left, slightly down. Then connect the origin with the end of Line 2.
 
Welcome to PF!

Hi victoria! Welcome to PF! :smile:

Think of it like a river … you point the boat in a particular compass direction, but when you get to the other side you find that the flow of the river has carried you downstream.

The first side of the triangle is your velocity relative to the water, the second side is the velocity of the water! :smile:

(oh … and always draw little arrows on the sides of your triangles! :smile:)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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