Guaranteeing turbulent flow in a gas pipe

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SUMMARY

The discussion centers on the necessity of achieving turbulent flow during gas pipe purging, as outlined in the IGEM publication IGE/UP/1. It establishes that minimum purge velocities must increase with pipe diameter to maintain turbulence and prevent laminar flow, which can leave residual gas. The friction factor for natural gas is defined as 0.0044 [1 + 43.5 d^-1], indicating that as pipe diameter increases, the friction factor decreases, necessitating higher flow velocities to keep shear stress constant. This relationship is crucial for ensuring effective purging and preventing gas buildup.

PREREQUISITES
  • Understanding of turbulent vs. laminar flow in fluid dynamics
  • Familiarity with the concept of Reynolds number
  • Knowledge of the Fanning friction factor and its application
  • Basic principles of gas flow in pipelines
NEXT STEPS
  • Study the IGEM publication IGE/UP/1 for detailed purging standards
  • Learn about the calculation of Reynolds number in gas flow
  • Research the implications of shear stress in fluid dynamics
  • Explore advanced fluid dynamics simulations for gas flow in pipes
USEFUL FOR

Gas engineers, pipeline maintenance professionals, and anyone involved in ensuring safe and effective gas purging operations will benefit from this discussion.

Jehannum
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In the gas industry engineers often have to purge gas pipes. For example, if repair work must be done on a gas line the fuel gas in the system must be removed before work can be done safely.

The Institute of Gas Engineers and Managers (IGEM) publication IGE/UP/1 stresses the need to achieve a minimum purge velocity when purging, to ensure that purge flow is turbulent. Laminar flow could leave undisturbed layers of fuel gas (of a different density to the purge gas) in pipes.

To help engineers achieve this IGEM provide a table that gives minimum purge velocity for a given pipe diameter. Some sample figures are below:

50 mm pipe, 0.6 m / s
...
200 mm pipe, 0.7 m / s
...
400 mm pipe, 1.0 m / s

My question is this: if Reynolds number for gas in a circular pipe is proportional to pipe diameter, why is a faster purge velocity needed for larger pipes? Wouldn't it be the opposite, i.e. a larger pipe diameter would mean you could have a slower purge velocity and still get the Reynolds number you need (say > 4000) to ensure turbulent flow?
 
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Maybe you need to have a certain shear stress at the wall. For turbulent flow, if f = 0.079/Re^0.25, how would the velocity vary with diameter so that the shear stress is constant?
 
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After going around in circles in Wikipedia and other sources I think I'm beginning to get a glimmer of sense. I have found out:

(Fanning) friction factor is the ratio between shear stress and flow kinetic energy density​

So I surmise that:

Friction factor is proportional to shear stress divided by the square of flow velocity​

Rearranging this tells me that:

Shear stress is proportional to friction factor x the square of flow velocity​

In the purging standard (see original post), it says that friction factor can be taken as 0.0044 [1 + 43.5 d^-1] for natural gas, where d = pipe diameter (mm). In terms of proportionality:

Friction factor decreases with increasing pipe diameter​

So, to keep shear stress constant:

If pipe diameter increases, flow velocity must increase, which is what we see in the tables in the purging standard.​

Would this chain of reasoning be correct? To understand all this I have had to make drastic simplifications: i.e. reducing equations to "if one thing goes up, this other thing goes down", but this is sufficient for my conceptual understanding - and it answers my original question.

Can you tell me why it could be necessary that shear stress be constant?
 
Jehannum said:
After going around in circles in Wikipedia and other sources I think I'm beginning to get a glimmer of sense. I have found out:

(Fanning) friction factor is the ratio between shear stress and flow kinetic energy density​

So I surmise that:

Friction factor is proportional to shear stress divided by the square of flow velocity​

Rearranging this tells me that:

Shear stress is proportional to friction factor x the square of flow velocity​

In the purging standard (see original post), it says that friction factor can be taken as 0.0044 [1 + 43.5 d^-1] for natural gas, where d = pipe diameter (mm). In terms of proportionality:

Friction factor decreases with increasing pipe diameter​

So, to keep shear stress constant:

If pipe diameter increases, flow velocity must increase, which is what we see in the tables in the purging standard.​

Would this chain of reasoning be correct? To understand all this I have had to make drastic simplifications: i.e. reducing equations to "if one thing goes up, this other thing goes down", but this is sufficient for my conceptual understanding - and it answers my original question.

Can you tell me why it could be necessary that shear stress be constant?
If there is some kind of deposit or buildup at the wall, it takes a higher shear stress to sweep it away.
 
I tried to do a curve fit to the relationship you gave. It seemed to be fit well by ##V=0.544e^{0.00148 D}##. This doesn't seem to relate to constant shear stress at the wall.
 
As well as minimum purge velocity they also give minimum purge flow rate (Qp). This figure is actually given to more significant figures. Here is the full range they give in the table:

[diameter (mm), Qp (m3 / h)]
[20, 0.7]
[25, 1.0]
[32, 1,7]
[40, 2.5]
[50, 4.5]
[80, 11]
[100, 20]
[125, 30]
[150, 38]
[200, 79]
[250, 141]
[300, 216]
[400, 473]
[450, 575]
[600, 1230]
[750, 2390]
[900, 3440]
[1200, 6960]
 
From this data, I get ##Q=0.0006492D^{2.2533}##. Plot the data, and see what you get.
 

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