Gyroscope coupling force force question

AI Thread Summary
The discussion centers on understanding the forces acting on a gyroscope, particularly in relation to a video demonstrating a spinning cheese wheel. Key questions include the momentum preventing the cheese from falling and how to calculate the force required to bring it down while maintaining constant RPM from an electric motor. There is confusion regarding the omega value in gyroscopic calculations, as it appears to be zero in the video, yet a significant coupling force is observed. The inquiry highlights a need for clarification on gyroscopic principles and their practical applications. Overall, the thread seeks expert insights into these gyroscopic dynamics.
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Hello everyone,

I saw this video in youtube:
And I have some questions, can someone please explain me the forces acting on this gyro? what is the momentum that keeps the cheese from falling, the direction of its action don't add up to me

Also, how could i calculate the force needed to take down the cheese to the ground given that the RPM is constant (electric motor), unlike in the video above?

i tried using the following website after reading about gyros:
http://www.gyroscopes.org/math.asp
what i don't understand is the omega part, it seems to be zero in the youtube video so how come the coupling force is so big?

Thanks a lot,
sharon
 
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