Half equation for S2O32-/S4O62- couple

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The discussion centers on writing the half equation for the S2O32-/S4O62- redox couple, highlighting difficulties due to their identical ionic values. Two proposed equations are presented: the first includes water and sulfur, while the second focuses solely on stoichiometry and electrons. The second equation is noted to have a charge balance issue, although the first is questioned for its adherence to conventional practices in redox equations. The conversation emphasizes the importance of balancing charges and the appropriate use of water and electrons in half equations. Ultimately, clarity on stoichiometry and charge balance is crucial for accurately representing the redox couple.
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I need to write the half equation for the S2O32-/S4O62- redox couple but I'm having trouble because they have the same ioic value.

I've come up wth two solutions but am happy with nether...

S2O32- + 3H2O + S2= S4O62- + 6H+ + 6e-

or

2S2O32- = S4O62- + 2e-

I know that the second one is wrong because the charges don't balance, but I'm not sure that the first is right either because we generally only add water, or electrons to the equations, so I'm not sure that I can add the S2.

am i just being obtuse or?!?
 
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Try ignoring any use of water. Just concentrate on the stoichiometry and the use of electron(s).
 
the charges DO balance in the second one.

2S2O32- = -4

S4O62- + 2e- = -4
 

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