Harmonic oscillation displacement

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Homework Help Overview

The discussion revolves around harmonic oscillation, specifically focusing on the displacement of a mass attached to a spring when released from a certain position. The original poster presents a scenario involving a ball pulled down from equilibrium and oscillating at a specified frequency.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of sine and cosine functions to describe the displacement, questioning the necessity of a phase shift based on the initial conditions of the problem. There is discussion about the implications of different coordinate systems on the choice of function.

Discussion Status

Some participants provide guidance on the use of sine and cosine functions, suggesting that the choice depends on the defined coordinate system. There is acknowledgment of the original poster's uncertainty regarding the correct representation of the displacement function, and others encourage testing different functions to see which aligns with the scenario described.

Contextual Notes

Participants note the importance of the initial displacement and how it affects the choice of function and phase shift. There is a mention of the original poster's lack of confidence in their physics understanding, which influences their approach to the problem.

Vitani11
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Homework Statement


...when she pulls the ball down 2.5cm from equilibrium and releases it from rest, it oscillates at 5.5 Hz. What is displacement y as functions of t?

Homework Equations


Y= Acos(omega t+phi)

The Attempt at a Solution


I'm almost certain I should instead be using sin to characterize the displacement or add in a phase angle of pi to the cosine function since its released from bottom. Is this a correct assumption?
 
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You can use either sin or cos to describe harmonic motion. Whether or not you need to incorporate a phase constant depends upon your choice of coordinate system (is the down direction considered positive or negative?) and where you want to place your initial position. As long as the resulting math describes your scenario as interpreted though your choices, everything's good.
 
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Yes I know this but I don't have any confidence in my ability to do physics so I need a clarification that this is not just cosine without a phase change, but sine or cosine with a phase change
 
Vitani11 said:
Yes I know this but I don't have any confidence in my ability to do physics so I need a clarification that this is not just cosine without a phase change, but sine or cosine with a phase change
You should be able to try them all and check them by plugging in a few values to see if what you've got matches your scenario. That's how you make the knowledge stick.

Ultimately whether or not you'll need a phase constant depends on how you choose your coordinate system. In this case if you chose "down" to be positive then a simple cosine will do, or a sine with a phase shift of ##\pi/2##. If "up" is positive (so that the initial displacement is taken to be negative) then a cosine or a sine, both with phase shifts, will work.

Sketch out a few wavelengths of a sine and a cosine function. Mark the major angles along the axis. You should be able to see how sine and cosine are the same basic form with just a phase shift to distinguish them. You can use a sketch like this to choose a function and phase shift to suit your purpose.
 
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Vitani11 said:

Homework Statement


...when she pulls the ball down 2.5cm from equilibrium and releases it from rest, it oscillates at 5.5 Hz. What is displacement y as functions of t?

Homework Equations


Y= Acos(omega t+phi)

The Attempt at a Solution


I'm almost certain I should instead be using sin to characterize the displacement or add in a phase angle of pi to the cosine function since its released from bottom. Is this a correct assumption?
No, because at t=0 your y displacement value is 2.5cm. If you use the sine (without a pi/2 addition in the argument) you'd get y=0 at t=0 which is wrong.
 
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Agreed I finished this yesterday and turned it in - thank you though.
 
So do you want to keep us in suspense until you get it back marked, or reassure us that you submitted 'displacement from equilibrium ##= -2.5 \cos (2\pi\;5.5\; t)## ' ?
(Oops...)
 
Lol I did exactly that except I defined down to be positive so it was −2.5cos(2π5.5t) without the sign.
 
I won't have it back marked for a week
 

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