sam_bell
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I've been looking at the original Herman-Skillman program that solves for the energy levels of a single atom using Hartree-Fock with Slater exchange orbitals. There is one part I can't understand: the expression of the correction to the energy level for a good guess. What the program *does* is: (1) set R^{out}(E_guess,r) = 0 for r = 0 and then numerically integrates out to r = r_match = classical turning point; (2) set R^{in}(E_guess,r) = 0 for r = infinity = end of grid, and then numerically integrates into r = r_match; (3) Computes logarithmic derivatives \gamma = R'(r_{match})/R(r_{match}) on both sides; and (4) sets dE =
ignore -->(( ignore ignore ))<---
\frac{ \gamma_{out}-\gamma_{in} }{ \int_0^{r_{match}} R_{out}^2/R_{out}(r_{match})^2 + \int_{r_{match}}^{\infty} R_{in}^2/R_{in}(r_{match})^2 }
I don't know how I would show that works.
Hoping for some helpful suggestions. Thx.
ignore -->(( ignore ignore ))<---
\frac{ \gamma_{out}-\gamma_{in} }{ \int_0^{r_{match}} R_{out}^2/R_{out}(r_{match})^2 + \int_{r_{match}}^{\infty} R_{in}^2/R_{in}(r_{match})^2 }
I don't know how I would show that works.
Hoping for some helpful suggestions. Thx.