Has the Ball Passed Its Highest Point Based on Velocity Vector?

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SUMMARY

The discussion centers on a physics problem from "Fundamentals of Physics 8th Edition Extended, Chapter 4, Checkpoint 3," regarding the velocity vector of a fly ball represented as v->=25i-4.9j m/s. The participant questions whether the ball has passed its highest point, interpreting the negative j component (-4.9j) as an indication of downward motion. The consensus among forum members is that the ball has not yet reached its maximum height, contradicting the participant's belief that the negative component signifies it is falling.

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ProRip
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This is a question from "Fundamentals of Physics 8th Edition Extended, Chapter 4, Checkpoint3."

"At a certain instant, a fly ball has velocity v->=25i-4.9j (the x-axis is horizontal, the y-axis is upward, and the v-> is in metres per second). Has the ball passed its highest point?

The answer in the book says it hasn't...?

But I believe it has as -4.9j means the ball is now falling towards the ground therefore it has past its max height within the projectile motion.

Am I incorrect, or is the book wrong??, If I'm incorrect can someone point out why?
 
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Welcome to PF!

Hi ProRip ! Welcome to PF! :smile:
ProRip said:
"At a certain instant, a fly ball has velocity v->=25i-4.9j (the x-axis is horizontal, the y-axis is upward, and the v-> is in metres per second). Has the ball passed its highest point?

The answer in the book says it hasn't...?

But I believe it has as -4.9j means the ball is now falling towards the ground therefore it has past its max height within the projectile motion.

Yup … minus j means it's moving downward …

looks as if the book is wrong! :redface:
 

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