Having a problem with inverse proportion

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The discussion focuses on solving a problem related to inverse proportion, specifically where variable b is inversely proportional to a squared (b ∝ 1/a²). A user seeks help in finding the value of x and has shared their attempt for review. Another participant explains how to express the relationship mathematically by removing the proportionality sign and substituting known values to find the constant k. The conversation emphasizes the importance of showing one's work when seeking assistance. Overall, the thread aims to clarify the steps needed to solve inverse proportion problems effectively.
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Reaaly need to solve these
 

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Hello mc2_phy, welcome to PF! :smile:

As per the rules, you need to show us your attempt before asking for help. :)
 
I have attached a file of attempt :) Dont know how to find x
 

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mc2_phy said:
I have attached a file of attempt :) Dont know how to find x

For which question have you posted this attempt?

Lets take the second for instance where b is inversely proportional to a^2.
We can write ##b \propto \frac{1}{a^2}##. Removing the proportionality sign, ##b =\frac{k}{a^2}## where ##k## is some constant.
Substitute ##a## and ##b##, find the value of k.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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