Having trouble graphing a Volume problem

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    Graphing Volume
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Homework Help Overview

The discussion revolves around a volume problem involving the graph of the function y=e^x, the line x=0, and the horizontal line y=π. Participants are exploring how to accurately graph the region bounded by these curves in preparation for calculating the volume generated by rotation about the x-axis.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to graph the line y=π and whether it can simply be represented as y=3.14. There is also discussion about the boundaries of the region and the shape formed when the area is rotated.

Discussion Status

There is ongoing exploration of the graphing process, with some participants providing confirmations of the graphical representation. However, there is no explicit consensus on the final interpretation of the graph or the volume calculation method.

Contextual Notes

Participants mention constraints related to attachment approvals for visual aids, which may affect the clarity of the discussion. There is also an indication of uncertainty regarding the intersection points of the curves involved.

BlackMamba
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Hello again,

Once I get this graphed correctly, I don't see any problems as to why I couldn't solve it. But for now I have a question about graphing this volume problem.

The problem says to find the volume generated by rotating the region bounded by y=e^x, x=0, and y=\pi about the x-axis.

I have a picture of what I my graph would look like. The green curve is the line y=e^x, and the rust colored line is, x=0. My question is where do I graph y=\pi ? Is it as simple as placing the line at y = 3.14?

Thanks for taking a look. It is greatly appreciated.
 

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I still am unsure about this. I could use the help. Thanks.

Actually I think I got it. But if you could look at confirm or deny what I have come up with I would appreciate it.
 

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Last edited:
I'd love to confirm what you have, however, for some reason the attachment is "pending approval." I can't view it.

Left boundary is a vertical line at x=0. Right and bottom boundary is y=e^x. Top boundary is y=pi. There's an intersection point where y=e^x and y=pi meet. It should look like a triangle. Then you rotate about the x-axis.

I didn't bother attaching a picture since attachments on this forum need some approval.
 
BlackMamba said:
...My question is where do I graph y=\pi ? Is it as simple as placing the line at y = 3.14?

Yes, it is as simple as placing a line parallel to the x-axis at y = 3.14.
 
Thanks fire and radou.

Fire ~ Your description is what my graph looks like so thanks again.
 

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