Austin0 said:
In principle I would [and have] agree
I agree that any event that could possibly occur would have coordinates.
The question of assigning specific coordinates to hypothetical events is the question I am posing.
That doesn't make any sense--the very idea of taking a hypothetical about physics as a premise is to imagine a universe where the hypothetical
really occurs and see what consequences would follow in such a universe. If you are imagining a universe where FTL is still purely hypothetical, then you aren't taking FTL as a premise in the first place!
If gave the if-then conditional "if I was standing in the open and it was raining, then I would get wet", would you then disagree since hypothetical rain can't get people wet the way real rain does? Your own statement above appears every bit as senseless.
Austin0 said:
Once again I would [and have] in principle agree completely. But dt<dx is a range of possible coordinates and the methods and logic of assigning a specific quantitative dt is the core of the question.
Again that doesn't make any sense. If we have a general proof that for
any set of coordinates that satisfy dx>dt in some inertial frame, there must then be an inertial frame where the events occur in reverse order, then naturally this proof would apply to whatever "specific quantitative dt" and dx you happen to imagine occurring in the hypothetical. Perhaps you are arguing that there would be some difficulty calculating dt in the first place, but that doesn't make sense either--you agreed earlier that in a relativistic universe we should be able to assign x and t coordinates to any event, so that means you can find the t coordinates of the event of the signal being sent and the event of the signal being received, and dt is just the second t coordinate minus the first t coordinate.
Austin0 said:
Do you realize these questions are a physics version of the classic "Do you like women , yes or no?" Well , yes
DO you think it is wrong to hit women, yes or no?"
Yes
"If you answered yes to the first two, then have you stopped beating your wife ,,,yes or no?"
That analogy doesn't make any sense, because there is no logical reason that answering yes to the first two questions would compel you to answer yes to the question about beating your wife. In contrast, I'm just trying to lead you through the inescapable logic of the proof, so I've specifically chosen questions such that if you answer yes to all of them, it becomes obvious that you have
no choice but to answer yes to the question of whether the premises of SR and FTL signaling together imply the conclusion of backwards-in-time signaling.
Austin0 said:
Through the course of this discussion I think I have come to understand your point of view and can see how, from that perspective , some of what I have been saying would seem "illogical" . I also completely agree that in this situation with many if-conditional premises it is necessary to focus on the center. The premise/argument that
"the events had a dx of 20 and a dt of 10 in the first frame"
This is the focus , both the quantitative value of dt and also the assumption that was the basis of this assigment.
No, that particular value of dt is
not the focus. As I said, it is easy to come up with a general mathematical proof that if the coordinates of two events in one frame are such that dx>dt, then it is
always possible to come up with a velocity v such that when you use that v in a Lorentz transformation, the order of the two events is reversed in the second frame. Would you like to see this proof, or do you agree that such a general proof is possible?
If you do agree, then it should be easy to see that for
any specific choice of coordinates for the transmission-event and the reception-event such that dx>dt--whether (0,0) and (20,10) or (50,70) and (60,79.999) or (-16.5,3000) and (501,3007)--it will be possible to find a different inertial frame where the events happen in reverse order according to t-coordinates assigned by the new frame.
Austin0 said:
Can I assume that if you had simply assigned a dt=(-10 ) in this premise that you would understand how I would see it as "including the conclusion in the premises" ??
Of course, but it is not obvious that the premise "FTL" is synonymous with the possibility that the reception-event happens before the transmission-event, while it
is obvious that FTL should be synonymous with the notion that dx>dt in some inertial frame. Of course the point of the proof is to show that if you take SR as a premise, then the latter "obvious" implication of the premise FTL implies the former "not-so-obvious" implication of the premise FTL. That's the difference between a vacuous tautology and a non-vacuous proof where the conclusion is still logically implied by the premise but it may not be immediately obvious that it follows just by looking at the premises.
Austin0 said:
AS I understand your point; because the actual assignment dt=10 did not obviously imply time travel and therefore required a transformation between frames to arrive at dt=-10 there was no inclusion of this conclusion in the premises.
OK I can see your point, even if the two times are effectively the same through a simple transform and the only real difference is that by deriving B from A instead of
A from B was ,,that this way it was not directly including the conclusion in the premises.
Yes, but again, in all mathematical proofs you can show that the conclusion is logically
implicit in the premises, but in the case of non-vacuous proofs you have to go through some steps--like the "simple transform" above--to demonstrate this. Incidentally, for a
specific choice of coordinates like (0,0) and (20,10) it's true that you just need to apply the transform with a particular choice of velocity to show that they can happen in reverse order in another frame, but it may not be obvious that for
any choice of coordinates for the events such that dx>dt, it would
always be possible to find a velocity such that when you plug that velocity and those coordinates into the Lorentz transform, the result is that the events happen in reverse order in the new frame. This is why I offered to provide a proof of this claim if you doubt it.
Austin0 said:
But in actuality there is reason to see ( dt=10 ) as directly indicating and requiring time travel. That for that dt to occur would mean going back in time 6 sec in frame A
That at t=0 ,x=0 x'=0, t'=0 from the perspective of frame B ( x=20) in A was colocated with x'=12 and had a time of t=16 AS frames always have local agreement and overall agreement this would seem to indicate a time discrepancy at x=20 from 16 --> 10 sec.=(-6)
What is your take on this?
Are you asking where the x=20 marking on A's ruler was at time t'=0 in B's frame? If so, yes, the answer is that it was next to the x'=12 mark on B's ruler, and at the moment the x=20 mark on A's ruler was passing next to the x'=12 mark on B's ruler, the clock attached to the x=20 mark on A's ruler must have read:
t = 1.666... *(0 + 0.8*12) = 16.
So, when you say "this would seem to indicate a time discrepancy at x=20 from from 16 --> 10 sec.=(-6)", are you talking about the time between the moment the clock at x=20 on A's ruler is next to the event of the tachyon signal being received, and the moment the clock at x=20 on A's ruler is next to the x'=12 mark on B's ruler? If so, then yes, according to A's clock at x=20, the event of the tachyon signal being received happens 6 seconds prior to the event of passing next to the x'=12 mark on B's ruler. Why do you bring this up? How is it relevant to the discussion?
Austin0 said:
That simply translates to "Well we know that time travel will happen in one frame so it must happen in all frames"
I am talking about an explicit premise IF a tachyon goes back in time 6 sec in frame A THEN time travel and how that would effect the significance of the overall argument.
Huh? The tachyon doesn't go back in time 6 seconds in A's frame. In A's frame, the event of the clock at x=20 passing next to the x'=12 mark on B's ruler is
not simultaneous with the event of the tachyon signal being sent, these events are only simultaneous in B's frame. So, the fact that in A's frame the event of receiving the signal happens 6 seconds before the event of x=20 passing next to x'=12 in no way implies that the tachyon has gone backwards in time in this frame. In A's frame the order of the events is this:
t=0: tachyon signal emitted next to x=0 mark on A's ruler (and next to x'=0 mark on B's ruler)
t=10: tachyon signal received next to x=20 mark on A's ruler (and next to x'=20 mark on B's ruler)
t=16: x=20 mark on A's ruler passes next to x'=12 mark on B's ruler
On the other hand, in B's frame the order of these events is this:
t'=-10: tachyon signal received next to x'=20 mark on B's ruler (and next to x=20 mark on A's ruler)
t'=0: tachyon signal emitted next to x'=0 mark on B's ruler (and next to x=0 mark on A's ruler),
AND simultaneously at a different location, x'=12 mark on B's ruler is passing next to x=20 mark on A's ruler.
I assume that by now you understand about the relativity of simultaneity, so you should be able to see that the fact that those two events happen simultaneously at t'=0 in B's frame does
not imply they should be simultaneous in A's frame.
Austin0 said:
The applicability of the addition of velocities equation.
There is absolutely no need to use the addition of velocities equation in the proof, you can just focus on the coordinates assigned to the events of the signal being sent and the signal being received. However, it's also not hard to show that if you take two events on the worldline of an object moving at constant speed, and calculate dx and dt between these events in one frame and define the velocity in that frame as dx/dt, then if you apply the Lorentz transformation to these two events and calculate dx'/dt' in the new frame, you
will find that the velocities in the two frames are related by the velocity addition equation, even in the case that dx>dt (i.e. you are looking at the worldline of a tachyon). If you'd like to see a proof of this, just ask.
Austin0 said:
The overall results of the application of the basic assumption to bi-directional assigments and the many questions that arise from those results. Questions of logic, physics and conformity to the first postulate.
I don't understand what "bi-directional assignment" means, and I don't know what "questions of logic, physics and conformity to the first postulate" you're referring to. Let me restate the steps in the proof as clearly as I can, and since you've already said you agree with the first 4 steps, maybe you can point out specifically what step you have a problem with:
1. Given the premise SR, we must assume that any events can be assigned space and time coordinates x and t in any inertial frame.
2. Given the premise FTL, there must be some inertial frame where, if you have the coordinates (x1,t1) of the signal being sent and the coordinates (x2,t2) of the signal being received, then in units where c=1, dx=|(x2-x1)| > dt=|(t2-t1)|
3. Given the premise SR, the coordinates assigned to the same event by different inertial frames must be related by the Lorentz transform.
4. Given 2 and 3, if you have a signal such that dx>dt for the transmission-event and the reception-event in one inertial frame, it is always possible to find a new inertial frame such the reception-event happens at an earlier time than the transmission-event in the new frame.
5. By the first postulate of SR, if it is possible in one frame to send a tachyon signal in such way that the reception-event happens at an earlier time than the transmission-event in that frame, it must be possible in
any frame to send a tachyon signal in such a way that the reception-event happens earlier than the transmission-event in that frame.
6. If it's possible in any frame to send a tachyon signal in such a way that the reception-event happens earlier than the transmission-event in that frame, then it must be possible for one observer to send a tachyon message to the other and the second to then send a tachyon reply in such a way that the event of the first observer receiving the reply lies in the past light cone of the event of the first observer sending the original message, which is a clear violation of causality in every frame.
Can you point to a specific step that you disagree with here, where you think that it doesn't follow from the previous steps and the original premises of SR and FTL?