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Yes, you're right about that.Austin0 said:Maybe I am not following you here, but isn't the propagation of sound independent of the source but measured to be different in relative frames??
That the difference with light is that it is also measured to be the same in all frames.
I still haven't figured out what you mean by "bidirectional speed".Austin0 said:I was not talking about the measured speed being the same in all frames. As I have mentioned elsewhere I think that due to clock desynchronization , they not only couldn't be measured at the same speed in different frmes but that they also couldn't be measured as having equal bidirectional speed in any frame.
Yes.Austin0 said:Assume you were doing an analysis of the measurement of light within two different frames.
Wouldnt you clock emmission and reception in one frame , and then from that frame calculate the emmission and reception in the other frame??
Absolutely not. The "actual reception" is an event, i.e. a point in spacetime. That point is assigned coordinates by all coordinate systems, and none of the inertial coordinate systems is "preferred" over any of the others.Austin0 said:That within the first frame there would be actual reception of photons but within that frame there would only be the hypothetical observation
by an observer at the proximate site of the actual reception in the second frame?
No, the A (="there's a largest prime number N) is false, since there are infinitely many primes. What I posted is the easiest way to prove that. The "if-then" statement is definitely corrrect.Austin0 said:Excuse me but in this case isn't it that 'A' [the IF] is in fact true, but it is the THEN "B' conclusion that is false? That in fact this statement is in no way valid.
No, that's the statement we proved. The premise (or postulate, axiom, or whatever you prefer to call it) is SR+FTL.Austin0 said:Isnt it the case that the premises are IF SR + FTL THEN time travel.
The A is "SR+FTL". The FTL part can be made explicit in many different ways, and one of them is to say that a particle emitted at the origin can be detected at (10,20). (t=10,x=20).Austin0 said:That in this case the A is A =assumption of event at ( x=20, t=10) <==> B=time travel ?
Wouldnt you agree that this is treating it as a proof of B the conclusion?
I'm confused by your second question. You're talking about proofs as if you can prove stuff without first assuming something. You obviously can't. We're not proving B. We're proving "if A then B". We're treating the result as a proof of "if A then B", because that's what it is.
Yes, since one of the assumptions is the conclusion.Austin0 said:If the statement was IF SR and IF FTL and IF a signal sent from A arrives 10 sec before it is sent in B THEN "timetravel "
Would you agree that this, although a valid argument, would be an obvious tautology and without significance as a proof of "time travel" ?