What Does F Represent in Group Theory?

  • Thread starter MikeDietrich
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In summary, "F" is a set that contains all real-valued functions of real argument with domain R. In other words, it is a set of all functions where the input and output are both real numbers. Some examples that would fall into set "F" are functions like x^2, x-1, |x|, and x^5-5x+sin(x). However, functions like 1/x and (x,x) are not included in "F" because they do not meet the requirements for the domain and codomain.
  • #1
MikeDietrich
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Hi-

Let me first start by saying that I do not have a mathematics background and I have a feeling my question is a moronic one but my attempts with "google" did not help so here I am.

I am about to do an assignment (but this is not a homework question IMHO) that asks me to determine if "F", with various operations, are groups. "F" is defined as:

"the set of all real-valued functions of real argument with domain R".

I do not know exactly what this means. In other words, what is "F"? Can someone give some some examples that would fall into set "F"? Or a good link with explanation?

Regards,
Mike
 
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  • #2
In f lie every function of the form [tex]f:\mathbb{R}\rightarrow \mathbb{R} [/tex].

Examples:
[tex] \mathbb{R}\rightarrow \mathbb{R}: x\rightarrow x^2 [/tex]
[tex] \mathbb{R}\rightarrow \mathbb{R}: x\rightarrow x-1 [/tex]
[tex] \mathbb{R}\rightarrow \mathbb{R}: x\rightarrow |x| [/tex]
[tex] \mathbb{R}\rightarrow \mathbb{R}: x\rightarrow x^5-5x+sin(x) [/tex]

Counterexamples:
[tex]\mathbb{R}\rightarrow \mathbb{R}: x\rightarrow 1/x [/tex] (is not defined in 0, so the domain is not entire [tex]\mathbb{R}[/tex]
[tex] \mathbb{R}\rightarrow \mathbb{R}: x\rightarrow (x,x) [/tex] (the element (x,x) is not in the codomain [tex]\mathbb{R}[/tex], but in [tex]\mathbb{R}^2[/tex]).
 
  • #3
Perfect. Thank you.
 

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