Heads or tails? (Question from Feynman lectures)

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The discussion centers on understanding the probability of getting heads in coin tosses using the formula (n choose k) = n! / (k!(n-k)!). The confusion arises regarding the placement of factorials in the equation, specifically why k! and (n-k)! are in the denominator rather than n! in the denominator and k! in the numerator. The explanation highlights that the formula calculates the number of ways to achieve k heads from n tosses. An example with n = 5 is suggested to illustrate how the formula applies. The lectures referenced were actually given by Matt Sands, not Feynman himself.
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I have been going through feynmans lectures on probability and have a few questions that i can't answer ; in the part regarding fluctuations he introduces us to tree diagrams(pascals triangle ) and gives an example regarding the toss of a coin
If we consider the no. Of tosses as n and no. Of heads as k then it can be given as
( n) n!
( k ) = ----
k!(n-k)!
I know that n! Represents n factorial and the fact that probability is generally
Given by
Probability = highest estimate of an event
----------------------------
Total no. Of events
However what i don't get is why do we multiply k! By (n-k)! Souldnt it be n! In the denominator and k! In the numerator ?
I know it has something to do with the triangle however unable to figure it out
 
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#neutrino said:
I have been going through feynmans lectures on probability and have a few questions that i can't answer ; in the part regarding fluctuations he introduces us to tree diagrams(pascals triangle ) and gives an example regarding the toss of a coin
If we consider the no. Of tosses as n and no. Of heads as k then it can be given as
( n) n!
( k ) = ----
k!(n-k)!
I know that n! Represents n factorial and the fact that probability is generally
Given by
Probability = highest estimate of an event
----------------------------
Total no. Of events
However what i don't get is why do we multiply k! By (n-k)! Souldnt it be n! In the denominator and k! In the numerator ?
I know it has something to do with the triangle however unable to figure it out
The equation is (n)= n!
(k) -----
k!(
 
The equation is (n)= n!
-----
k!(n-k)!
 
You're actually asking, I think, about how many ways you can get ##k## heads from ##n## coin tosses. And why the answer is ##\frac{n!}{(n-k)! k!}##

You could start by taking ##n = 5##, say, and counting all the ways you can get ##k = 0, 1, 2, 3, 4## and ##5##.

Then see whether that fits the formula, and why.
 
BTW (just in case anyone is interested), this was not Feynman's lecture, but Matt Sands' lecture. Feynman had to go out of town on some business for a week, so Matt Sands gave the lectures that became FLP Vol. I Chapters 5 and 6.
 
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