Heat and increasing a rod's length

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Homework Help Overview

The discussion revolves around a problem involving the thermal expansion of a metal rod, specifically focusing on how to calculate the energy required to increase its length by a specified amount. The problem includes parameters such as the rod's dimensions, coefficient of linear expansion, density, and heat capacity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between volume and length changes due to thermal expansion, questioning whether mass remains constant during heating. Some suggest focusing solely on the change in length rather than volume.

Discussion Status

There is an ongoing exploration of the problem, with participants providing insights into the fixed nature of mass and the implications of density changes. Some guidance has been offered regarding the relevance of length versus volume in the context of the problem.

Contextual Notes

Participants note that the problem's specifications emphasize the change in length, leading to discussions about the implications of volume changes and the necessity of determining the temperature increase required for the desired length change.

Lisa Marie
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Homework Statement


A 1.0m long rod of metal has a diameter of 0.75 cm. This metal has a coefficient of linear expansion α = 4.8 × 10−5 1/K , a density of 9.7 × 103 kg/ m3 , and a heat capacity of 390 J/K . How much energy needs to be added as heat to increase the length of the rod by 7.5 × 10−3 m?

Homework Equations


V0=πr2h
ΔV=βV0ΔT
m=vρ

The Attempt at a Solution


V0=πr2]h
=π(0.0075/2)2(1)
=4.42×10-5

V0=πr2h
=π(7.5×10-3+1)(0.0075/2)2
=4.45×10-5

ΔV=βV0ΔT
ΔT=ΔV/(3αV0)
=(4.45×10-5-4.42×10-5)/(3(4.42×10-5))

m=vρ where do I go from here? Because the the mass would always be changing
 
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The mass is fixed. Probably the density will change.
 
NascentOxygen said:
The mass is fixed. Probably the density will change.

So you would do M=∫ρdV to find the mass?
 
You know the rod's dimensions and its density, so can determine mass. This mass doesn't change when you apply heat to expand it.

I'm wondering why you involve ΔV when all that is required is ΔL? I could be wrong, but it seems that you are making the problem more difficult than is intended.
 
NascentOxygen said:
You know the rod's dimensions and its density, so can determine mass. This doesn't change when you apply heat to expand it.

I'm wondering why you involve ΔV when all that is required is ΔL? I could be wrong, but it seems that you are making the problem more difficult than is intended.

Ok thanks! I'll try it with just change in length but doesn't the volume change since the length is changing?
 
Lisa Marie said:
Ok thanks! I'll try it with just change in length but doesn't the volume change since the length is changing?
Certainly volume will change when length and diameter change. But the problem specs centre on the change in length.
 
NascentOxygen said:
Certainly volume will change when length and diameter change. But the problem specs centre on the change in length.
So I should use this volume:
V0=πr2h
=π(0.0075/2)2(1)
=4.42×10-5
...because I'm not getting the right answer
 
You are attacking the problem backwards. How much of a temperature increase do you need to increase the length by the desired amount? What is the mass of the rod?

Chet
 

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