Heat and work in adiabatic container

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SUMMARY

The discussion centers on the principles of thermodynamics in an adiabatic container where electrical current passes through a resistor immersed in a liquid. It is established that no heat (q) flows across the boundary due to the adiabatic nature of the system, leading to the conclusion that the change in internal energy (ΔU) is equal to the work (w) done on the system. The relationship ΔU = PextΔV is highlighted, indicating that work is performed as the temperature of the liquid increases, thereby increasing its internal energy.

PREREQUISITES
  • Understanding of thermodynamics, specifically the first law of thermodynamics.
  • Familiarity with adiabatic processes and their implications on heat transfer.
  • Knowledge of internal energy and its relationship with temperature changes.
  • Basic concepts of work in physics, particularly in thermodynamic systems.
NEXT STEPS
  • Study the first law of thermodynamics and its mathematical formulations.
  • Explore adiabatic processes in detail, including examples and applications.
  • Learn about the relationship between internal energy, temperature, and work in thermodynamic systems.
  • Investigate different types of work done in physics, particularly in closed systems.
USEFUL FOR

Students of physics, particularly those studying thermodynamics, as well as educators and anyone interested in the principles of energy transfer in closed systems.

kiwikahuna
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Homework Statement



Electrical current is passed through a resistor immersed in a liquid in an adiabatic container. The temperature of the liquid is varied by 1 degree celsius. The system consists solely of the liquid. Does heat or work flow across the boundary between the system and surroundings? Justify your answer.


The Attempt at a Solution



Because it is an adiabatic container, heat does not flow across the boundary between the system and surroundings. So...d[tex]\Delta[/tex]U = q +w where q = 0.

[tex]\Delta[/tex]U = w
[tex]\Delta[/tex]U = Pext[tex]\Delta[/tex]V

I'm having a hard trying to find the right way to explain that work is being done in physics lingo. Is it because temperature of the liquid increases the internal energy therefore work is being done?

Thanks.
 
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kiwikahuna said:
I'm having a hard trying to find the right way to explain that work is being done in physics lingo. Is it because temperature of the liquid increases the internal energy therefore work is being done?

Yes, and if you wanted to be more detailed you could talk about what kind of work is being done and the nature of the "force" that is doing work.
 

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