Heat equation with a Fourier Series on an infinitely long rod

Click For Summary

Homework Help Overview

The discussion revolves around solving the heat equation for an infinitely long rod, specifically focusing on the application of Fourier series to determine the coefficients for the solution based on given initial conditions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to determine the coefficients B_n for the Fourier sine series representation of the solution. They question whether to treat the length L as a large number or as 2, given the initial conditions defined over a specific interval.

Discussion Status

Some participants are engaging with the problem, with one expressing a lack of success and seeking clarification on the original poster's approach. There is an indication of ongoing exploration of different interpretations regarding the setup of the problem.

Contextual Notes

There is a noted ambiguity regarding the treatment of the infinitely long rod in relation to the defined initial conditions, particularly concerning the integration limits for calculating the coefficients.

nyt
Messages
2
Reaction score
0

Homework Statement



The heat equation for an infinitely long rod is shown as:

<br /> \alpha^2 \frac{\partial^2}{\partial x^2}u(x,t) = \frac{\partial}{\partial t}u(x,t) <br />

<br /> u(0,t) = u(L,t) = 0,\ \forall \ t &gt; 0<br />

<br /> u(x,0) = sin(\pi x) \ \forall \ 1 &lt; x &lt; 2<br />
<br /> u(x,0) = 0\ \forall \ otherwise<br />

<br /> \alpha^2 = 0.1<br />2. The attempt at a solution

I know that the solution of this problem is a Fourier sine series:

u(x,t)= sum (n=0 to infinity) B_n * sin ((n pi x)/L)

However, I am having problem trying to determine the coefficient Bn:

<br /> B_n = \frac{2}{L}\int_{0}^{L} sin(\pi x) sin(\frac{n \pi x}{L}) dx <br />

Since the function u(x,0)= sin(pi x) for 10<x<11 I'm not sure if I should approach this as:
<br /> B_n = \frac{2}{L}\int_{1}^{2} sin(\pi x) sin(\frac{n \pi x}{L}) dx<br />
where L is a large number

OR

<br /> B_n = \frac{2}{2}\int_{1}^{2} sin(\pi x) sin(\frac{n \pi x}{2}) dx<br />Do I go ahead with the second one and ignore that the rod is infinitely long since u(x,0) = 0 for all other values or is this a mistake?

I apologise that some of the equations of the post look like this but I couldn't get my tex brackets to work.
 
Last edited:
Physics news on Phys.org
I believe I've figured this out.

How can I edit/remove posts?

Thanks.
 
nyt,

im working on the same problem but I am not having much success, i was wonder how u solved the problem
 
justiz1 said:
nyt,

im working on the same problem but I am not having much success, i was wonder how u solved the problem

What is your struggle exactly?
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K