Heating water with amps ohms and time

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Discussion Overview

The discussion revolves around calculating the final temperature of water when heated using electrical current, specifically focusing on the relationship between current, resistance, time, and heat transfer. The context includes theoretical and mathematical reasoning related to physics concepts, particularly in thermodynamics and electrical power.

Discussion Character

  • Exploratory, Technical explanation, Homework-related, Mathematical reasoning

Main Points Raised

  • One participant proposes using the equation q=mC(Tf-Ti) and q=IT to find the final temperature of the water, suggesting a formula Tf= (Rt/vCm)+Ti.
  • Another participant expresses uncertainty about the correct application of Ohm's law, admitting to a mistake in their initial approach regarding the relationship between current, voltage, and resistance.
  • A third participant questions the clarity of the original post, specifically asking for clarification on what "24.7" refers to in the context of the discussion.
  • The same participant provides a hint about calculating power, noting the relationship between volts, amps, and watts.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to the problem, and multiple competing views regarding the calculations and concepts remain unresolved.

Contextual Notes

There are limitations in the discussion, including missing values for voltage and resistance, which are critical for calculating power and heat transfer. Additionally, the units and their relationships are not fully clarified, leading to further uncertainty.

speny83
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so if i have 89.6g water at 304K and a constant p=1.00bar and i heat it by running 1.75A through 24.7 for 105 seconds what will the final temp be?


im thinking i can take q=mC(Tf-Ti) and q=IT and I=R/V

to say that Tf= (Rt/vCm)+Ti

i can't rember that much about physics and this stuff isn't in my book, yet its on my study list...First off will this work. it appears that it would. Secondly what units would one use to do this

the best i can figure the unit work would be something like (Ω*s)/(v*K-1g-1*g) but this is one of those funny things where i don't know what that corresponds to
 
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ya i screwed that up bad I=V/R and I don't have any value for V so no help...what on Earth do you do to something like this?
 
'running 1.75A through 24.7 for 105 seconds'

24.7 what?

You need to review how power is calculated knowing electric current:

http://en.wikipedia.org/wiki/Electric_power

Hint: 1 volt times 1 amp = 1 watt of power.
 

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