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## Homework Statement

Hey so this is a really trivial question.

f(t) = { 0, 0<= t < pi

{ -sin3t, t>=pi

Just having trouble properly shifting this!

## The Attempt at a Solution

f(t) = -u

_{pi}(t)sin(3t)

= -u

_{pi}(t)sin[3(t-pi+pi)]

= u

_{pi}(t)sin[3(t-pi+pi)]

How do I take the +pi out?

I know it should end up as:

u

_{pi}(t)sin[3(t-pi)]

I just don't really understand how from my last step.

thanks for reading!