Height of bullet at top of trajectory

AI Thread Summary
To determine the height a bullet reaches when fired straight up at 1000 mph, the kinematic equation V^2 = Vo^2 + 2ax can be applied, where V is the final velocity (0 at the peak), Vo is the initial velocity (1000 mph), a is the acceleration due to gravity (negative), and x is the height. For the second part, to find the angle for a bullet to have a speed of 100 mph at the peak, one must consider the horizontal and vertical components of the initial velocity, ensuring the vertical component equals zero at the height of the trajectory. The calculations involve using trigonometric functions to resolve the initial velocity into its components and applying energy conservation principles. Understanding these concepts and equations is crucial for solving the problem effectively. Accurate application of physics principles will yield the desired results for both parts of the question.
calnpals
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Ok guys, I'm stuck on this question I was wondering if you could help me out.

Its actually in 2 parts (2nd part harder than 1st part).

1st part: At what height will a bullet reach if fired at 1000mph straight up (excluding all other forces except gravity)

2nd part: At what angle would a bullet that is shot at 1000mph have to be shot at to have a speed of 100mph at the height of its trajectory, and what height would it reach?

Thanks
 
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It would be better if you showed some of your work.
Anyway, for the first part you just need a basic kinimatics equation
( V^2 = Vo^2 + 2ax) or you could use energy.
And for the second part, at the height of the trajectory the only speed is along the x-axis and the speed along that axis is the same throughout the whole trip. Does that make it any easier?
 
calnpals said:
Ok guys, I'm stuck on this question I was wondering if you could help me out.

Its actually in 2 parts (2nd part harder than 1st part).

1st part: At what height will a bullet reach if fired at 1000mph straight up (excluding all other forces except gravity)

2nd part: At what angle would a bullet that is shot at 1000mph have to be shot at to have a speed of 100mph at the height of its trajectory, and what height would it reach?

Thanks
How do you start ? What formula's will you use and more importantly why ?

marlon
 
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