Could a Helium 3 Fusion Reactor Power a Settlement on the Moon?

AI Thread Summary
Helium-3 (He-3) extraction from lunar regolith at 700 degrees Celsius for fusion reactions is a plausible concept for powering a lunar settlement. The fusion of He-3 with Deuterium could yield significant energy, making it an attractive option for space exploration due to its high energy density. While establishing a lunar colony and mining operations will be costly, launching fuel from the Moon would be cheaper than from Earth. However, achieving a controlled fusion reaction remains a significant challenge, and the efficiency of the reactor design is crucial for success. Overall, while the idea has merit, both fusion technology and lunar colonization face substantial hurdles.
IamQuarky
Messages
1
Reaction score
0
I have this project in school for settlement on moon. I have this idea that the large quantities of He 3 on moon could be extracted by heating the regolith at 700 degrees celsius and then could be taken to a reactor in which He 3 could be fused with Deuterium or itself. The heat produced could be harnessed by heat shields and then taken to a turbine for converting to electricity. Could this reactor work ? I read about this process online and i want someone to elaborate it for me .
Thanks for going through my question !
 
Engineering news on Phys.org
There's still the teeny-tiny difficulty of achieving a controlled fusion reaction.
 
  • Like
Likes Dr. Courtney and dlgoff
IamQuarky said:
I have this project in school for settlement on moon. I have this idea that the large quantities of He 3 on moon could be extracted by heating the regolith at 700 degrees celsius and then could be taken to a reactor in which He 3 could be fused with Deuterium or itself. The heat produced could be harnessed by heat shields and then taken to a turbine for converting to electricity. Could this reactor work ? I read about this process online and i want someone to elaborate it for me .
Thanks for going through my question !

Yes, this is plausible. There are several people who are promoting mining the moon for He-3 to both power a lunar colony and to use as a power source for further space exploration. Fusion is a attractive fuel for space exploration because it is very energy dense. Also as you probably know it is very expensive to launch anything into space from Earth. It costs about $10,000 to launch 1 pound into space. The moons gravity in much weaker than Earth's. After we establish a lunar colony, it will be much cheeper to launch fuel into space from the moon than from Earth. (Of course establishing a lunar colony will not be cheep).

I know one proponent of this idea is Harrison Schmitt. He was an astronaut on Apollo 17, and as a geologist he is the only scientist who walked on the moon. He taught a course on resources from space at the university of Wisconsin a while ago, and the lecture notes were publicly available. Unfortunately, the website is down right now. But with a little bit of google-fu you might be able to find them backed up somewhere.Of course as others are quick to point out fusion isn't ready yet, but then again we're not colonizing the moon either. Both are challenging problems. Don't let that stop you.
 
3He + D releases 18 MeV of energy. Lunar regolith concentrations of 3He are up to 80 ppb, or 1.4 eV per atom of regolith processed. Heating material to 700 degrees needs about 0.1 eV per atom, but you can gain back some part of it with a clever heat exchange design. It is possible, but the margin is not so large. Your fusion reactor should be highly efficient. Using pure helium fusion reduces the energy gain to 6.5 MeV per atom of 3He, nearly a factor 3 worse. On the positive side, it would avoid DD fusion as side-reaction, this reaction leads to neutron activation of the reactor walls.
 
Hello, I'm currently trying to compare theoretical results with an MCNP simulation. I'm using two discrete sets of data, intensity (probability) and linear attenuation coefficient, both functions of energy, to produce an attenuated energy spectrum after x-rays have passed through a thin layer of lead. I've been running through the calculations and I'm getting a higher average attenuated energy (~74 keV) than initial average energy (~33 keV). My guess is I'm doing something wrong somewhere...

Similar threads

Replies
5
Views
4K
Replies
3
Views
3K
Replies
16
Views
6K
  • Poll Poll
Replies
12
Views
2K
Replies
18
Views
4K
Replies
23
Views
9K
Back
Top