HELP Calculating contact angle of benzene.

AI Thread Summary
To calculate the contact angle of benzene on glass, the experiment shows that benzene rises 1.71 mm while water rises 4.90 mm in a capillary tube at 20.0 C. Given the densities and surface tensions of both liquids, the relevant equation involves the surface tension of benzene, water, and the contact angle. The challenge lies in determining the surface tension of the glass surface, which is not provided. It is suggested that the surface tensions might be inferred from the water data, but clarity on how to derive these values is needed. The discussion emphasizes the need for a clear starting point in the calculations.
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Homework Statement



In an experiment to determine how well benzene wets glass, benzene was found to rise to 1.71 mm in a certain capillary tube at 20.0 C. In the same tube, water rose 4.90 mm at 20.0 C. Calculate the contact angle for benzene, give that at 20.0 C, benzene = 0.879 gcm^-3, pwater = 0.998 gcm^-3, benzene = 2.89 * 10^-2 Nm^-1 and ywater = 7.28 * 10^-2 Nm^-1. The contact angle for water is assumed to be theta = 0.

Homework Equations


y1 = cosθ + y1,2 - y2 = 0


The Attempt at a Solution



I don't know where to start. I know y1 can be found by finding the capillary radius of water and using that for benzene. But how do you find y1,2 and y2? Aren't they surface tensions of the solid glass surface which is not given?
 
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At first glance, and without working it on paper - can't you calculate them from the information about water?
 
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