HELP Can anyone PLEASE give me a hand with this limit? THANKS ;)

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SUMMARY

The limit of the sequence defined by a(n) = [1 + sin(n*pi/3)cos(n*pi/5)] / [n^0.5] as n approaches infinity can be computed using the sandwich theorem. The key insight is that both sine and cosine functions are bounded between -1 and 1, which allows for establishing an upper bound for the numerator. Consequently, the limit evaluates to 0 as n increases, since the denominator grows without bound while the numerator remains bounded.

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CathyC
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1. Use the sandwich theorem to compute the limit as n goes to infinity of the sequence with the following nth elements:

a(n) = [1 + sin(n*pi/3)cos(n*pi/5) ] / [n^0.5]

I would really appreciate some help with this one guys. If you could please go slow with the answer as my trig is pretty shaky. Thanks for all your help! :)

Cathy
 
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You don't really have to use a lot of trig. -1<=sin(x)<=1 and the same for cos(x). No matter what x is. Suggest an upper bound for the value of the numerator.
 

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