Help deriving expression for the error in velocity.

AI Thread Summary
The discussion focuses on deriving the error expression for velocity based on the equation v_x = s/sqrt(2h/g). Participants emphasize the importance of correctly applying error propagation rules, particularly for division and square roots. There is clarification that for independent variables, the Root Sum of Squares method is appropriate for calculating uncertainties. Additionally, it is noted that the relative error for a square root is half that of the original quantity. Understanding these principles is crucial for accurately determining the error in velocity calculations.
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Homework Statement


Derive the error expression \delta v_{}x from the equation v _{x}=\frac{s}{sqrt(\frac{2h}{g})}

The Attempt at a Solution



I've derived error expressions before, but I have a history of getting the calculations right and the error equations wrong. So, if possible I'd like to have someone tell me what I am doing wrong (if anything) when I derive this.

For any two numbers divided by one another (2h/g), the error z is:

\deltaz=|z|(\frac{\delta x}{|x|} + \frac{\delta y}{|y|})
So:
\deltaz=|z|(\frac{\delta h}{|h|} + \frac{\delta g}{|g|})

At this point intuition tells me that I should just multiply that by two to get the error in 2(h/g), but I think I've done that before and got it wrong.

I have no idea what the error of a square root is. I'm going to guess it's the same as the error in squaring something, so the error in the initial equation would be:

\deltav=|v|(\frac{2 \delta h}{|h|} + \frac{2 \delta g}{|g|} + \frac{\delta s}{|s|})

So, am I right? If not, what am I doing wrong? It's fairly crucial to understand these rules, I think, so any help would be wonderful.

Thanks.
 
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Vasili said:

Homework Statement


Derive the error expression \delta v_{}x from the equation v _{x}=\frac{s}{sqrt(\frac{2h}{g})}

The Attempt at a Solution



I've derived error expressions before, but I have a history of getting the calculations right and the error equations wrong. So, if possible I'd like to have someone tell me what I am doing wrong (if anything) when I derive this.

For any two numbers divided by one another (2h/g), the error z is:

\deltaz=|z|(\frac{\delta x}{|x|} + \frac{\delta y}{|y|})
So:
\deltaz=|z|(\frac{\delta h}{|h|} + \frac{\delta g}{|g|})

At this point intuition tells me that I should just multiply that by two to get the error in 2(h/g), but I think I've done that before and got it wrong.

I have no idea what the error of a square root is. I'm going to guess it's the same as the error in squaring something, so the error in the initial equation would be:

\deltav=|v|(\frac{2 \delta h}{|h|} + \frac{2 \delta g}{|g|} + \frac{\delta s}{|s|})

So, am I right? If not, what am I doing wrong? It's fairly crucial to understand these rules, I think, so any help would be wonderful.

Thanks.

One thing I would note is that g is a gravitational constant that unless you are measuring it and using it generally doesn't carry an error or if it does carries a relative error of 0.
 
Well, the equation is a lab equation and they always give gravity along with its uncertainty. But is the rest of it right?
 
Vasili said:
Well, the equation is a lab equation and they always give gravity along with its uncertainty. But is the rest of it right?

Some treatments of uncertainty for independently measured variables take the Root Sum of the Squares of the relative uncertainties for multiplication division and the absolute uncertainties for addition subtraction. You will have to be the judge of what your lab may be wanting from you.

Your answer would be the more conservative approach as it would yield a greater resultant uncertainty.
 
As for exponents I think you take the exponent and multiply it times the relative uncertainty of the quantity being taken to the exponent. So for sqrt I think you take 1/2 the relative error quantity.
 
Oh, right. Square root is the same as taking it to the 1/2 exponent. I keep forgetting that, thanks.
 
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