*HELP* Finding x in [_,_] of Possible Inflection Points

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SUMMARY

The discussion focuses on finding possible inflection points of the function f(x) = esin(x) within the interval [0, 2π]. The second derivative f''(x) is derived as f''(x) = esin(x)(cos2(x) - sin(x)). To find inflection points, the equation cos2(x) - sin(x) = 0 is solved, leading to a quadratic equation in sin(x). The solutions yield two x-values in the specified interval, specifically x = 0.6662 radians and x = 2.476 radians.

PREREQUISITES
  • Understanding of calculus, specifically second derivatives
  • Familiarity with trigonometric identities and equations
  • Knowledge of solving quadratic equations
  • Proficiency in using inverse trigonometric functions
NEXT STEPS
  • Study the properties of the second derivative and its implications for concavity
  • Learn about the unit circle and how it relates to trigonometric functions
  • Explore the use of numerical methods for solving equations involving trigonometric functions
  • Practice finding inflection points for various functions beyond f(x) = esin(x)
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Students and educators in calculus, mathematicians analyzing inflection points, and anyone interested in advanced trigonometric applications.

  • #31
NoMoreExams said:
Well try plugging that into your calculator :)

Yay:!)
 
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  • #32
There you go champ :)
 
  • #33
thanks (still didnt tell me your name) :) now i just have to finish the rest of the assignment lol
 
  • #34
The beauty of the anonymity of the Internetz ;-)
 
  • #35
NoMoreExams said:
The beauty of the anonymity of the Internetz ;-)

haha okay Genius, thanks for the helpo:)
 
  • #36
Genius - far, far, far from it but you are welcome.
 
  • #38
Well why don't you do what Halls suggested?
 
  • #39
they cross twice in the first quadrant
that is y=cosx crosses y=x first and then it crosses y=1/5x
you know my main problem is that i can never understand what the question is actually asking for :(
 

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