- #31
AnnaSuxCalc
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NoMoreExams said:
Yay:!)
*HELP* Finding x in [_,_] of Possible Inflection Points
- Thread starter AnnaSuxCalc
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Homework Help Overview
The discussion revolves around finding possible inflection points of the function f(x) = e^sin(x) by analyzing its second derivative, f''(x). Participants are tasked with determining the x-coordinates of these points within the interval [0, 2π].
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants discuss factoring the second derivative and setting it to zero. There are attempts to clarify the implications of the hint regarding the function g(t) = e^t, which is never zero. Questions arise about the meaning of "possible inflection points" and how to find all relevant x-values in the specified interval.
Discussion Status
The conversation is ongoing, with participants exploring different methods to solve the equation cos^2(x) - sin(x) = 0. Some guidance has been provided regarding the quadratic form of the equation in terms of sin(x), and there is recognition of the need to find two solutions within the interval [0, 2π].
Contextual Notes
Participants express confusion about the problem's requirements and the implications of the solutions found so far. There is a focus on ensuring that all solutions are within the specified interval and that the values are expressed in radians.
Yay:!)
- #32
NoMoreExams
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There you go champ :)
- #33
AnnaSuxCalc
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thanks (still didnt tell me your name) :) now i just have to finish the rest of the assignment lol
- #34
NoMoreExams
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The beauty of the anonymity of the Internetz ;-)
- #35
AnnaSuxCalc
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NoMoreExams said:
haha okay Genius, thanks for the help
- #36
NoMoreExams
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Genius - far, far, far from it but you are welcome.
- #37
AnnaSuxCalc
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You can help with this too if youd like :D
https://www.physicsforums.com/showthread.php?t=285074
dont feel obligated haha
https://www.physicsforums.com/showthread.php?t=285074
dont feel obligated haha
- #38
NoMoreExams
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Well why don't you do what Halls suggested?
- #39
AnnaSuxCalc
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they cross twice in the first quadrant
that is y=cosx crosses y=x first and then it crosses y=1/5x
you know my main problem is that i can never understand what the question is actually asking for :(
that is y=cosx crosses y=x first and then it crosses y=1/5x
you know my main problem is that i can never understand what the question is actually asking for :(
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