HELP how to plug this into the calculator sigma notation?

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To calculate the sum of the series ∑ 2 cos(π/k) from k=1 to 4, first expand the summation into its individual terms: 2 cos(π/1), 2 cos(π/2), 2 cos(π/3), and 2 cos(π/4). The values of these terms are -2, 0, 1, and √2, respectively. Instead of using a calculator, you can directly compute these values and sum them up. For a TI calculator, use the command sum(seq(f(x),x,a,b,1) to set up the function. This method simplifies the calculation process and avoids discrepancies in results.
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how would i plug this into the calculator? to find the sum?
step by step process? thankss!

4
∑ 2 cos (π/k)
k = 1

i tried this site
http://mathbits.com/mathbits/tisection/Algebra2/summation.htm
and i got a different answer...so i just need help with the set up on a T.I calc.
 
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Why would you want to? This is a summation with four terms. Just expand the summation into its four terms.
 
\sum_{k= 1}^4 2 cos\left(\frac{\pi}{k}\right)= 2 cos\left(\frac{\pi}{1}\right)+ 2 cos\left(\frac{\pi}{2}\right)+ 2 cos\left(\frac{\pi}{3}\right)+ 2 cos\left(\frac{\pi}{4}\right)

Since cos(\pi)= -1, cos(\pi/2)= 0, cos(\pi/3)= 1/2, and cos(\pi/4)= \sqrt{2}/2, you shouldn't need to use a calculator.
 
for the function f(x) for x=a to x=b the screen should read

sum(seq(f(x),x,a,b,1)

you should be able to catalog or 2nd[math] to find the [sum(] and [seq(] operators

hope this helps
 
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