Help in integration i=1/L∫Vdt || V=(6t+26)/(t^2+10t+21)

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The discussion focuses on calculating the current i as a function of time t in a 5-henry inductor, where the induced emf is given by the formula V=(6t+26)/(t^2+10t+21). The integration of V leads to the expression i=1/5(ln(t+3)^2+ln(t+7)^4+k), where k is the integration constant. To finalize the current function, an initial condition is necessary to determine the value of k, which may depend on the circuit's state at t=0.

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I hope anyone could give me a hand on this one...

The induced emf in a 5-henry inductor varies as V=(6t+26)/(t^2+10t+21). Recalling that current i=1/L∫Vdt, find the formula for the current i as a function of time t.

This is what I've gotten so far...

∫(6t+26)/(t^2+10t+21)=(6t+26)/(t+3)(t+7)=A/(t+3)+B(t+7)=2/(t+3)+4/(t+7) dt

i=1/5∫2/(t+3)+4/(t+7)dt
i=1/5(ln(t+3)^2+ln(t+7)^4+k...

Well should I stop here since I've gotten only the variable t on the right side of the formula or should differentiate it since they are asking for the formula of currentas a function of time t? If so... is this correct?

di/dt=1/5{[(2t+6)/(t+3)^2]+[(4t+28)/(t+7)^4)]}

Thank you again guys...
 
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Sorry, I saw this one then lost it, and forgot. :blushing:

The expression for i(t) seems correct. But one would need and initial condition to solve for an integration constant, or if the limits of integration are t=0 (or to and t=t, one would hopefully have io, which could be zero if the circuit is open, or there is some constant (DC) current.

This question would be appropriate in electrical engineering or homework sections.
 

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