Help me Find a Vector of Length 6 with Same Direction!

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SUMMARY

The discussion focuses on finding a vector that has the same direction as the vector <-2, 4, 2> but with a specified length of 6. The user initially calculates the unit vector by determining the magnitude using the formula |v| = √(A1² + A2² + A3²) = √(24). The solution provided clarifies that to achieve the desired length of 6, one must multiply the unit vector by 6, resulting in the final vector of length 6 in the same direction.

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wtee85
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Okay so i need a little help.

Heres the problem.

The question asks...

Find a vector that has the same direction as <-2,4,2> but has length 6.

So i Did the |v|= Sqrt( A1^2+A2^2+A3^2)= sqrt(24) which is how you begin to find the unit vector with the same direction. I get stumped on how to find it with length 6. The new vector with the same direction would be... <-2/Sqrt(24), 4/Sqrt(24), 2/Sqrt(24)... but.. what about the length of 6..?

Can anybody help me? What do i do with this length of 6?

... any help would be awesome!
 
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You simply multiply your last vector by six. Because your last vector has the length of one, you would get a vector of length six just by simply multiplying your vector by 6. That's the whole point of unit vectors. They make calculations really easy. :biggrin:
 
Why the same post two times?
 

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