Help Me Hill Height for 35kg Child on 5kg Sled

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To determine the height of the hill a 35-kg child on a 5-kg sled descends, conservation of energy principles are applied. The child reaches a speed of 30 km/h at the bottom, indicating kinetic energy (KE) is present. The relevant formula for KE is 0.5mv², while potential energy (PE) at the top is expressed as mgh. The mass and angle of the hill are not needed for the calculation, allowing for a symbolic approach. The discussion emphasizes the importance of unit conversion for accurate results.
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Homework Statement


A 35-kg child goes down a hill on a 5-kg sled. Starting from rest, she reaches a speed of 30 km/h at the bottom of the hill. The hill makes an angle of 25 degrees with the horizontal.

(a) Assuming there is no heat generated by friction and air resistance, how high is the hill?

I don't really know how to solve this problem, help, please?
 
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Are you familiar with conservation of energy?
What form of energy does the child have at the bottom of the hill? Where did this energy come from?
Hint: In this case, the mass of the child and sled and the angle of the hill aren't required to find the answer (as long as you work symbolically and don't try to plug any numbers in until the very end, which is generally the best approach)
 
I am familiar with COE and I think it has KE at the bottom of the hill...?
 
GalacticSnipes said:
I am familiar with COE and I think it has KE at the bottom of the hill...?

Correct. And do you know the formula for KE? What form of potential energy did the sled start with? Do you know the formula for that form of energy?
 
would the whole formula be something like this: 0.5m(v)^2 = mgh?
 
GalacticSnipes said:
would the whole formula be something like this: 0.5m(v)^2 = mgh?

Correct. Good work. Be sure to use the appropriate unit for velocity, a conversion in necessary.
 
ok, thx
 
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