Help me in michelson interferometer

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SUMMARY

The discussion focuses on calculating the angular radius of the tenth bright fringe in a Michelson interferometer using two different central-path differences: 1.50 mm and 1.5 cm. The relevant equations are 2d sin θ = mλ and 2d cos θ = mλ, where λ is the wavelength of the orange light from a krypton arc, measured at 6057 Å. The user expresses confusion regarding the application of these equations and the nature of the interference pattern produced by the interferometer.

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Homework Statement



Find the angular radius of the tenth bright fringe in a Michelson interferometer
when the central-path difference (2d) is (i) 1.50 mm and (ii) 1.5 cm.
Assume the orange light of a krypton arc is used and that the interference is
adjusted in each case so that the first bright fringe forms a maximum at the
centre of the pattern.




Homework Equations



2d sin theta = m lambda or
2d cos theta= m lamda


The Attempt at a Solution


i confuse to use the equation.

theta= cos-1 or sin -1 (6057 armstrong x 10th) divide 1.50mm
the answer that i get is not logic.
 
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I'm unaware of circular fringes being produced in a Michelson interferometer. Ideally, there either is or isn't light at the detector or screen.

Is there any more information given in the problem statement?
 

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