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A block of mass 0.6 kg rests on the inclined
surface of a wedge of mass 1.8 kg. The wedge
is acted upon by a horizontal force F and slides on a frictionless surface.
The acceleration of gravity is 9.81 m/s
If the coefficient of static friction between
the wedge and the block is 1 and the angle of
the incline is 23º, find the minimum value of
F for which the block does not slip.
Answer in units of N
My attempt to a solution
I haven't done it b my plan is to find the normal force and friction to find the acceleration, but I noticed that in order for block to be still, mgcosθ should be equal to N and since the friction f = μN and μ=1, f = N so f = mgcosθ. It can't be right because f = Nsinθ and it just doesn't seem right. What should I do? Are there any mistake in my plan to solve this problem?
surface of a wedge of mass 1.8 kg. The wedge
is acted upon by a horizontal force F and slides on a frictionless surface.
The acceleration of gravity is 9.81 m/s
If the coefficient of static friction between
the wedge and the block is 1 and the angle of
the incline is 23º, find the minimum value of
F for which the block does not slip.
Answer in units of N
My attempt to a solution
I haven't done it b my plan is to find the normal force and friction to find the acceleration, but I noticed that in order for block to be still, mgcosθ should be equal to N and since the friction f = μN and μ=1, f = N so f = mgcosθ. It can't be right because f = Nsinθ and it just doesn't seem right. What should I do? Are there any mistake in my plan to solve this problem?