Help Needed With Stress Calculations for Steel & Brass Rods

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Homework Help Overview

The discussion revolves around stress calculations for steel and brass rods under tension. The original poster presents a problem involving a steel rod with a specified diameter and load, seeking assistance with the calculation of stress and extension. Additionally, a related question about a brass rod's stress and load is raised, highlighting the need for guidance on the relevant formulas.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the formula for stress as Force/Area but expresses uncertainty about the calculations and the necessary formulas for extension and stress in the brass rod. Some participants provide formulas related to stress and strain, while others question the units used in the calculations.

Discussion Status

Participants are exploring various formulas and concepts related to stress and strain. Some guidance has been offered regarding the relationships between stress, strain, and elasticity, but there is no explicit consensus on the calculations or methods to find the magnitude of the load.

Contextual Notes

The original poster mentions difficulties with self-teaching and accessing appropriate resources, indicating a potential gap in foundational knowledge that may affect their understanding of the problem.

donkey131
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I'm having problem knowing how to work out this question, can anyone point me in the correct direction.

Question
14mm diameter steel rod carries a load of 3.08kN in tension. calculate the stress.?

I ended up with this:
Stress = Force/Area.
Stress = 3.08/154 = Answer = 0.02N/mm²

if the rod is 2.5m long and the modulus of elasticity is 200GN/m2
how much will it extend?

so far i have know idea of the formula or how to work this out?
can anyone help please

I also have one other question related to stress that is

A brass rod measures 10mm in dia, and 150mm length. The rod extends 0.3mm when subjected to a load. given that brass E=85GN/m2
Calculate the stress in the material and the magnitude of the load:
if you could help with the formula that would be a big help.
I'm not able to find any thing on the net and the books i got from the library are over the top in calculations
please help
many thanks
 
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Hi donkey131, welcome to PF. For a rod undergoing axial loading, stress \sigma[/itex] and strain \epsilon[/itex] are related by the equation \sigma=E\epsilon[/itex].<br /> <br /> Make sure to check your units in your calculations.
 
Another formula that you will need is \epsilon= [l(final)-l(initial)]/l(initial)
 
so how do i now find the Magnitude.
 
not sure about this as I am trying to teach my self, it an NVQ course. NOt good teaching your self something you don't know.

Calculate the stress in the material and the magnitude.
10mm = Diameter steel rod
?? = Area of the rod
3.08kN = Tension
?? = Stress
?? = Strain
150mm = Length
0.3mm = Extends
85 GN/m² = Elasticity

Area:
Area = pi x radus² There for: Area = Pi (3.142) x 2.5² (6.25) = 19.637mm² (19.64)

Strain:
Strain = extension (change in Length)/Original Length
Strain = 0.3/150 = 0.002


There for we now can find the Stress:
Stress = Strain x Elasticity
Stress = 0.002 x 85 =0.17N/m²

Answer = 0.17N/m²

so how do i find Magnitude:?
 
The magnitude is just the absolute value of the number. If the stress is -5 N/m², for example, we describe it as a compressive stress with a magnitude of 5 N/m².

Again, recheck the units in your calculations - I see several errors.
 

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