a duralumin rod of 50mm diameter is a loose fit inside a mild steel tube of 60mm outside diameter. if the steel tube is turned down to 55mm diameter over one half its length, calculate the stress in the duralumin rod and the stress in each portin of the tube due to an akial load of 20KN. both rod and tube are the same length. E for steel=196GN/m^2 and E for duralumin = 126GN/m^2.
force=stress in duralumin*area of duralumin+stress in steel*area of steel
strain in steel=strain in duralumin
The Attempt at a Solution
stress in duralumin=load/area of duralumin
and im stuck any help plz