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cyrus35

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## Homework Statement

a duralumin rod of 50mm diameter is a loose fit inside a mild steel tube of 60mm outside diameter. if the steel tube is turned down to 55mm diameter over one half its length, calculate the stress in the duralumin rod and the stress in each portin of the tube due to an akial load of 20KN. both rod and tube are the same length. E for steel=196GN/m^2 and E for duralumin = 126GN/m^2.

## Homework Equations

force=stress in duralumin*area of duralumin+stress in steel*area of steel

strain in steel=strain in duralumin

## The Attempt at a Solution

stress in duralumin=load/area of duralumin

=20000/0.001963495409

=101,859,163.6N/m^2

and im stuck any help plz