Water is being sprayed at a hot flowing material to cool it from 350F to 290F. Lets assume that steam is produced when the water hits the hot material. How would I set up the heat transfer equation to solve for the mass flow rate of water required to cool it from 350 to 290? Assumptions Specific Heat of Water = 4.186 KJ/Kg-K Specific Heat of Hot Material = 2.177 KJ/Kg-k Mass Flow Rate of Hot Material = 1.512 Kg/s Latent Heat of Vaporization = 2260 KJ/Kg Temperature of Water = 75F Evaporation Temperature of Water = 212F This is how I set up the equation.... Energy absorbed by Water + Latent Heat of Vaporization - Energy released by Hot Material = 0 MFRwater*Cwater*(TwaterOUT-TwaterIN) + Lwater*MFRwater - MFRmaterial*Cmaterial*(TmaterialOUT-TmaterialIN) = 0 Now, solving for MFRwater ... MFRwater = [MFRmaterial*Cmaterial*(350-290)] / [Cwater*(212-75) + Lwater] When I plug in the numbers, I get a REALLY small answer. Am I missing a part of the equation? Is my algebra wrong? Am I using the right value for the specific heat of water, later heat of vaporization, and evaporation temperature of water? Or did I do everything correctly?