- #1
ComFlu945
- 9
- 0
I'm trying to follow some notes in class.
so the original equation is:
u= [ (x^2 – 1)^1/2 + ln (x + (x^2 – 1)^1/2 )]
and we let x=z+1.
Then by simplifying and approximating, u=z*2*2^.5 + higher order terms
from my notes: (x^2 – 1)^1/2 = (2z)^.5*(1+z/2)^.5
ln(1+e) approximately = e
so the original equation is:
u= [ (x^2 – 1)^1/2 + ln (x + (x^2 – 1)^1/2 )]
and we let x=z+1.
Then by simplifying and approximating, u=z*2*2^.5 + higher order terms
from my notes: (x^2 – 1)^1/2 = (2z)^.5*(1+z/2)^.5
ln(1+e) approximately = e