Help understanding a SR equation

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The discussion centers on the understanding of time intervals in Special Relativity, specifically the transformation of time measurements between two frames of reference, S and S`. The equation presented, t`1 - t`2 = γ((x2-x1)(u/c)^2), illustrates how time intervals are affected by relative motion. The confusion arises from the order of subtraction in the time interval, which is clarified by the transformation equation Δt' = γ(Δt - vΔx/c^2), leading to the conclusion that switching the order eliminates negative values. This insight is crucial for accurately interpreting time measurements in relativistic contexts.

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Reikoku
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Hi all, I'm currently a stage 1 Physics student at uni; and in the process of learning Special Relativity.

I was reading my textbook and came across this in the Time and Space section:

Suppose an observer in frame S measures two flashbulbs going off at the same time t but at different x-coordinates x1 and x2. Then an observer in frame S` would measure the time interval t`1 - t`2 between the flashbulbs going to be:

t`1 - t`2 = \gamma((x2-x1)*(u/c)^2)

I was wondering why it's t`1 - t`2 instead of the usual t`2 - t`1. I assume it's to prevent the final answer being negative? I feel like I'm being stupid asking this :|
 
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It's just to get rid of a minus sign. The full transformation is:
\Delta t' = \gamma(\Delta t - v\Delta x/c^2)

Since Δt = 0, you get:
\Delta t' = -\gamma(v\Delta x/c^2)

Where Δt' is the usual t'2 - t'1. But if you switch the order you can get rid of the minus sign on the right hand side.
 
Yeah that makes sense now, cheers! :D
 

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